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Diameter = 2(Pi)r = 8Pi Let O be the centre of the circle. Angle of ROU is [(4Pi/3)/8Pi] * 360 = 60 OR = OU =4 (radii) so the triangle ROU is isosceles. Since angle ROU is 60 this makes the triangle equilateral. RU = OR = OU = 4 ANS = D
sorry not absolutely sure where you got the original equation from. The arc (4Pi/3) is defined by a portion of the overall diameter. Arc + Line Segment will not give you the perimeter of the circle, only of the area bound by the line segment.
Unless I've misunderstood the question what is it asking for is the straight line segment. which will be 4.
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Check out this awesome article about Anderson on Poets Quants, http://poetsandquants.com/2015/01/02/uclas-anderson-school-morphs-into-a-friendly-tech-hub/ . Anderson is a great place! Sorry for the lack of updates recently. I...