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The positive integers x,y, and z are such that x is a factor

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Senior Manager
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The positive integers x,y, and z are such that x is a factor [#permalink] New post 01 Nov 2006, 21:37
00:00
A
B
C
D
E

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  5% (low)

Question Stats:

100% (02:48) correct 0% (00:00) wrong based on 2 sessions
The positive integers x,y, and z are such that x is a factor of y and y is a factor of z. Is z even?

1) xz is even
2) y is even.
Manager
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 [#permalink] New post 01 Nov 2006, 22:58
I get D.

To start, I applied the following rules:

Even x Even = Even
Even x Odd = Even
Odd x Odd = Odd

With that in mind...

Statement 1:

xz is even. This tells us that x and z are both even or one is even, and the other is odd.

From the question, we know that x and y are factors of z, and as such, the lowest value for z is xy. Replacing z with xy, we find that unless both x and y are odd, xy (thus z) must be even. Because statement 1 tells us that xz is even, x and y (the factors of z) can't both be odd. Going back to Even x Odd = Even, xy must be even. As a result, z must be even. Sufficient.

Statement 2:

Y is even. Going back to the rules above, we know that anything multiplied by an even number is even. Since y is a factor of z, it follows that z must be even. Sufficient.

Since both are sufficient on their own, I take answer D.
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 [#permalink] New post 02 Nov 2006, 12:24
St xz is even possible only one is even or both are even or odd even.
When x is even y is even and thus z is even when x is odd z has to be even.
thus suff

St2 states y is even thus x and z have to even

Thus answer is D
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 [#permalink] New post 02 Nov 2006, 12:59
1) Since x is a factor of z. All the factors of an odd number are always odd. Since x is a factor of z and if z is odd x has to be odd but
that can not be true because that will make 'xz' odd. So they are both even. SUFFICIENT.

2) Odd numbers can not have even factors. So, z is even.

D
  [#permalink] 02 Nov 2006, 12:59
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