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The present ratio of students to teachers at a certain

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The present ratio of students to teachers at a certain [#permalink] New post 26 Mar 2012, 02:48
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The present ratio of students to teachers at a certain school is 30 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers?

(A) 5
(B) 8
(C) 10
(D) 12
(E) 15

[Reveal] Spoiler:
This might be really embarrasing, since I normally score Q47 or higher, but this question really made me stumble.

What is wrong with my approach (I always use this approach on ratio questions and it normally works well):

Plug in E:

25:1 is the new ratio -> 1 = 1*15 = 15 teachers and 25 = 25*15 = 375 students

15 - 5 = 10 teachers before the increase
375 - 50 = 325 students before the increse

so the old ratio is 325 : 10 which is unequal to 30:1

Where is my mistake?

PS. No need to tell me others ways how to solve it. I am familiar with the 'equations ways'.


Cheers a lot and I am happy ti give away Kudos ;)
Lars
[Reveal] Spoiler: OA

Last edited by Bunuel on 07 Dec 2012, 05:59, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Slightly embarrasing [#permalink] New post 26 Mar 2012, 03:02
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Impenetrable wrote:
The present ratio of students to teachers at a certain school is 30 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers ?

5
8
10
12
15


This might be really embarrasing, since I normally score Q47 or higher, but this question really made me stumble.

What is wrong with my approach (I always use this approach on ratio questions and it normally works well):

Plug in E:

25:1 is the new ratio -> 1 = 1*15 = 15 teachers and 25 = 25*15 = 375 students

15 - 5 = 10 teachers before the increase
375 - 50 = 325 students before the increse

so the old ratio is 325 : 10 which is unequal to 30:1

Where is my mistake?

PS. No need to tell me others ways how to solve it. I am familiar with the 'equations ways'.


Cheers a lot and I am happy ti give away Kudos ;)
Lars


The very first step is not correct: the present ratio of students to teachers is 30 to 1, not 25 to 1. So if you want to plug t=15 you should use 30:1 ratio, not 25:1.

Complete solution:

Given: \(\frac{s}{t}=\frac{30x}{x}\) and \(\frac{30x+50}{x+5}=\frac{25}{1}\). Solve \(\frac{30x+50}{x+5}=\frac{25}{1}\) for \(x\) --> \(x=15\) --> \(t=x=15\).

Answer: E.

Hope it helps.
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Re: The present ratio of students to teachers at a certain [#permalink] New post 26 Mar 2012, 03:14
How stupid of me. I should slap myself.


Thanks a lot! ;)
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Re: The present ratio of students to teachers at a certain [#permalink] New post 26 Mar 2012, 03:16
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+1 E

Here's what I did
s/t = 30/1 => s=30T

S+50/t+5 = 25/1

Substitute S=30T in the above equation

30t+50 = 25t+125

5t = 75
t=15

I hope this helps. By the way I was facing the same situation & it helps if you just take a break. I couldnt even recognise simple s v errors :-p
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Re: The present ratio of students to teachers at a certain [#permalink] New post 25 Oct 2012, 01:28
I actually thought it would be easier to tackle this problem by plugging in the answers choices, but I was VERY wrong, it's just tedious and prone to errors for this exercise.

Straight algebra saves you at least 1 full minute and it's very simple in this case.

Thanks to Bunuel for the clarifications.
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Re: The present ratio of students to teachers at a certain [#permalink] New post 09 May 2013, 18:51
the first part seems to be the trickiest,\(\frac{S}{T}\) = \(\frac{30}{1}\), then cross multiply to get 30T=S
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Re: The present ratio of students to teachers at a certain [#permalink] New post 25 Jun 2014, 21:30
Hello from the GMAT Club BumpBot!

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The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 03:23
Hello,

I am referring to Bunuel's solution. Can somebody explain why we are setting up the equation using a variable for the first ratio (30x/1x), but not for the second one (25x/1x). This is what I did wrong when I tried to solve the problem.

Thanks,

P.
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Re: The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 09:05
Expert's post
Pasqualo wrote:
Hello,

I am referring to Bunuel's solution. Can somebody explain why we are setting up the equation using a variable for the first ratio (30x/1x), but not for the second one (25x/1x). This is what I did wrong when I tried to solve the problem.

Thanks,

P.


If you write the first ratio as 30x/x, then you cannot write the second one as 25x/x, because x's there are not the same. You could write it as 25y/y though.

Does this make sense?
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Re: The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 09:32
Thanks for the quick answer Bunuel. I understand that the two ratios are different and should be translated into two different variables (say x and y), but how do we solve for two variables if we do that?

e.g,: 30x + 50 = 25 y (x+5)

I hope I am making sense here. Basically, I don't understand why we use the first ratio with a variable and the second one as a normal numeric value. By the way, thanks for your amazing work on this forum.

Cheers
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The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 09:44
Expert's post
Pasqualo wrote:
Thanks for the quick answer Bunuel. I understand that the two ratios are different and should be translated into two different variables (say x and y), but how do we solve for two variables if we do that?

e.g,: 30x + 50 = 25 y (x+5)

I hope I am making sense here. Basically, I don't understand why we use the first ratio with a variable and the second one as a normal numeric value. By the way, thanks for your amazing work on this forum.

Cheers


If you use two variables, the second one will be simply reduced, that's why we don't need it.

\(\frac{30x+50}{x+5}=\frac{25y}{y}\) --> reduce by y: \(\frac{30x+50}{x+5}=\frac{25}{1}\) --> solve for x.

Hope it's clear.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 09:56
Great, now it's crystal clear. Thanks again
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Re: The present ratio of students to teachers at a certain [#permalink] New post 02 Aug 2014, 22:45
E is the answer. The best way to solve this problem is using equations I think. You can work a different way by using the answer choice to check.
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Re: The present ratio of students to teachers at a certain [#permalink] New post 06 Aug 2014, 21:19
\(\frac{s}{t} = \frac{30}{1}\)

\(\frac{s+50}{t+5} = \frac{25}{1}\)

Placing s=30t in the above equation

30t+50 = 25t+125

5t = 75

t=15

Answer = E
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Re: The present ratio of students to teachers at a certain [#permalink] New post 11 Sep 2014, 09:49
Impenetrable wrote:
The present ratio of students to teachers at a certain school is 30 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers?

(A) 5
(B) 8
(C) 10
(D) 12
(E) 15

[Reveal] Spoiler:
This might be really embarrasing, since I normally score Q47 or higher, but this question really made me stumble.

What is wrong with my approach (I always use this approach on ratio questions and it normally works well):

Plug in E:

25:1 is the new ratio -> 1 = 1*15 = 15 teachers and 25 = 25*15 = 375 students

15 - 5 = 10 teachers before the increase
375 - 50 = 325 students before the increse

so the old ratio is 325 : 10 which is unequal to 30:1

Where is my mistake?

PS. No need to tell me others ways how to solve it. I am familiar with the 'equations ways'.


Cheers a lot and I am happy ti give away Kudos ;)
Lars




I have resolved using plug in method & got E.. worst method for this question ..
Re: The present ratio of students to teachers at a certain   [#permalink] 11 Sep 2014, 09:49
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