The price per share of Stock X increased by 10 percent over

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The price per share of Stock X increased by 10 percent over [#permalink]

18 Dec 2012, 06:47

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Re: The price per share of Stock X increased by 10 percent over [#permalink]

18 Dec 2012, 06:51

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The price per share of Stock X increased by 10 percent over the same time period that the price per share of Stock Y decreased by 10 percent. The reduced price per share of Stock Y was what percent of the original price per share of Stock X ?

Let the initial price per share of stock X be x, so after increase by 10% it would become 1.1x;
Let the initial price per share of stock Y be y, so after decrease by 10% it would become 0.9y.

Question: \frac{0.9y}{x}=\frac{9y}{10x}=?

(1) The increased price per share of Stock X was equal to the original price per share of Stock Y --> 1.1x=y --> \frac{9y}{10x}=\frac{9*1.1x}{10x}=0.99 or 99%. Sufficient.

(2) The increase in the price per share of Stock X was 10/11 the decrease in the price per share of Stock Y --> 1.1x-x=\frac{10}{11}*(y-0.9y) --> 0.1x=\frac{10}{11}*0.1y --> 1.1x=y the same info as in (1). Sufficient

Answer: D.
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Re: The price per share of Stock X increased by 10 percent over [#permalink] 18 Dec 2012, 06:51

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The price per share of Stock X increased by 10 percent over

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The price per share of Stock X increased by 10 percent over

The price per share of Stock X increased by 10 percent over

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