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The price per share of stock X increased by 10 percent over [#permalink]
 15 Sep 2003, 03:37
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The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1. The increased price per share of stock X was equal to the original price per share of stock Y
2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y
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Answer D
If X is original proce of stock x and Y original price of stock y.
then we are asked to find : 0.9Y/X
1) 1.1X = Y => we can calculate above ratio, thus suffecient.
2) 0.1X=10/11*0.1Y => we can calculate above ratio, thus suffecient.
- Vicks
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This is DS problem. Could anyone try to explain the rationale for the answer?
219
The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1. The increased price per share of stock X was equal to the original price per share of stock Y.
2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.
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I believe D is the answer.
Reduced price of Y is 0.9Y and original price of share X is X
so 0.9Y = k * X we need to determine K here.
A) 1.1X = Y
We have 0.9Y = K * X so K = 0.9Y/X = 0.9 * 1.1 X / X = 0.99
B) 0.1 X = 10/11 * 0.1 Y or X = 10Y/11
We have K = 0.9Y/X so K = 0.9Y * 11 / 10Y = 0.99
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I got D too. 
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The price per share of stock x increased by 10% over the same time period that the price per share of stock Y decreased by 10%. The reduced price per share of stock y was what percent of the original price per share of stock x?
(1) The increased price per share of stock x was equal to the original pricer per share of stock y?
(2) The increase in the price per share of stock x was 10/11 the decrease in the price per share of stock y.
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ggarr wrote: The price per share of stock x increased by 10% over the same time period that the price per share of stock Y decreased by 10%. The reduced price per share of stock y was what percent of the original price per share of stock x?
(1) The increased price per share of stock x was equal to the original pricer per share of stock y?
(2) The increase in the price per share of stock x was 10/11 the decrease in the price per share of stock y.
X became 1.1 X and Y became 0.9 Y
we need to figure out 0.9Y/X = ?
From 1) we have 1.1x = y so Y/X = 1.1 hence SUFF
From 2) 0.1 X = 10/11 (0.1 Y) Again you can get X/Y so SUFF
Answer D
what is the OA?
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DS: stock price % increase (OG #111) [#permalink]
09 Sep 2008, 23:52
The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1) The increased price per share of stock X was equal to the originial price per share of stock Y
2) The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y
Please expand on answers
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Re: DS: stock price % increase (OG #111) [#permalink]
10 Sep 2008, 01:29
D droopy57 wrote: The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1) The increased price per share of stock X was equal to the originial price per share of stock Y
2) The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y
Please expand on answers D 1) 1.1x = y suff 2) .1x * 11/10 = .1y suff
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The price per share of stock X [#permalink]
28 Aug 2010, 11:11
The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
(1) The increased price per share of stock X was equal to the original price per share of stock Y.
(2) The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.
I got lost in the above options and did not understand how to solve each. Will appreciate if someone (may be Bunuel) can help solve (1) and (2).
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Re: The price per share of stock X [#permalink]
28 Aug 2010, 11:28
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seekmba wrote: The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
(1) The increased price per share of stock X was equal to the original price per share of stock Y.
(2) The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.
I got lost in the above options and did not understand how to solve each. Will appreciate if someone (may be Bunuel) can help solve (1) and (2). Let the initial price per share of stock X be x, so after increase by 10% it would become 1.1x; Let the initial price per share of stock Y be y, so after decrease by 10% it would become 0.9y. Question: \frac{0.9y}{x}=\frac{9y}{10x}=?(1) 1.1x=y --> \frac{9y}{10x}=\frac{9*1.1x}{10x}=0.99 or 99%. Sufficient. (2) 1.1x-x=\frac{10}{11}*(y-0.9y) --> 0.1x=\frac{10}{11}*0.1y --> 1.1x=y the same info as in (1). Sufficient Answer: D.
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Re: The price per share of stock X [#permalink]
28 Aug 2010, 12:31
Thanks Bunuel.
I did not understand how you arrived at the below equation.
Question: 0.9y/x = 9y/10x = ?
The reduced price per share of stock Y (0.9y) was what percent of the original price per share pf stock X (x). The reason I put ?/100 is because we do not know the percentage and thats what we have to find out. What am I missing here??
--->0.9y = (x) X (?)/100
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Re: The price per share of stock X [#permalink]
28 Aug 2010, 12:41
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seekmba wrote: Thanks Bunuel.
I did not understand how you arrived at the below equation.
Question: 0.9y/x = 9y/10x = ?
The reduced price per share of stock Y (0.9y) was what percent of the original price per share pf stock X (x). The reason I put ?/100 is because we do not know the percentage and thats what we have to find out. What am I missing here??
--->0.9y = (x) X (?)/100 You got the same thing: 0.9y=\frac{x*?}{100} --> ?=\frac{0.9y}{x}*100, where "?" represents the value we are looking for. The only difference is that you have it already transformed in percents and I have it as fraction. Generally if we are asked m is what percent of n then: %=\frac{m}{n}*100.
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Re: The price per share of stock X [#permalink]
28 Aug 2010, 14:15
Ok so i was on right track. Thanks a bunch aagain
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Re: The price per share of stock X [#permalink]
05 Mar 2011, 21:44
i did it right : ans D
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I got the problem correct. I just want to make sure my algebra translations are on point. Can someone please walk me through the algebra? Thanks!
The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1. The increased price per share of stock X was equal to the original price per share of stock Y.
2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.
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tonebeeze wrote: I got the problem correct. I just want to make sure my algebra translations are on point. Can someone please walk me through the algebra? Thanks!
The price per share of stock X increased by 10 percent over the same time period that the price per share of stock Y decreased by 10 percent. The reduced price per share of stock Y was what percent of the original price per share of stock X?
1. The increased price per share of stock X was equal to the original price per share of stock Y.
2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y.
| Stocks Data |
| Stock Name | Price/Share(2005) | Increase/Decrease in Price | Reduced/Increased Price/Share(2010) |
| X | x | 0.1x Increase | 1.1x (Increased Price) |
| Y | y | 0.1y Decrease | 0.9y(Reduced Price) |
Table above shows the price of stock X and Y in 2005 and 2010(duration of time for the change is same). Rest of the fields are self-explanatory. Q: The reduced price per share of stock Y was what percent of the original price per share of stock X? 0.9y=(\frac{WHAT}{100})*xWHAT=(\frac{0.9*100y}{x})WHAT=(\frac{90y}{x})Rephrase: Q: What is \frac{y}{x}? 1. The increased price per share of stock X was equal to the original price per share of stock Y. 1.1x=y\frac{y}{x}=1.1Sufficient. 2. The increase in the price per share of stock X was 10/11 the decrease in the price per share of stock Y. 0.1x=\frac{10}{11}*0.1y\frac{y}{x}=\frac{11}{10}\frac{y}{x}=1.1Sufficient. Ans: "D"
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X2 = 1.1X Y2 = 0.9Y So Y2/X = ? (1) -> X2 = Y => 1.1X = Y2/0.9 => Y2/X = 99/100 sufficient (2) -> X2 - X = 10/11(Y - Y2) => 1.1X - X = 10/11(0.1Y) => 0.1X = 0.1Y * 10/11 => X = Y * 10/11 => X = 10Y2 / 9 * 10/11 => Y2/X = 99/100 Sufficient Answer - D
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Answer is D. Posted from my mobile device 
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Percents - "Stock Comparison" Question [#permalink]
15 Aug 2011, 18:00
The price per share of Stock X increased by 10 percent over the same time period that the price per share of Stock Y decreased by 10 percent. The reduced price per share of Stock Y was what percent of the original price per share of Stock X?
1. The increased price per share of Stock X was equal to the original price per share of Stock Y.
2. The increase in price per share of Stock X was 10/11 the decrease in the price per share of Stock Y.
A) Statement 1 is sufficient alone.
B) Statement 2 is sufficient alone.
C) Both statements together are sufficient, but not separately.
D) Each statement separately is sufficient.
E) Statements 1 and 2 statement together are not sufficient.
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Percents - "Stock Comparison" Question
[#permalink]
15 Aug 2011, 18:00
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