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# The probability for event A to occur is 0.6, and for B to

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The probability for event A to occur is 0.6, and for B to [#permalink]

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24 Apr 2006, 02:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The probability for event A to occur is 0.6, and for B to occur is 0.5. What is the probability that neither event A nor event B will occur?
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24 Apr 2006, 02:45
9/10

(1-6/10)+(1-5/10)=9/10.
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24 Apr 2006, 02:57
(1-6/10)*(1-5/10) = 20/100 = 1/5 = 0.2
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24 Apr 2006, 04:26
If we assume that A and B are independant, then we have:
P(N)=1-[P(A)+P(B)-P(AnB)]
=1-[6/10+5/10 - 6/10*5/10]
=1-[11/10- 3/10]
=1-[8/10]
=2/10
=0.2

Is that correct?
(N=Neither A, nor B)
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24 Apr 2006, 07:02
OA is 0.2

Thanks guys!
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24 Apr 2006, 10:26
Ethan wrote:
OA is 0.2

Thanks guys!

OOOPPPSSS

It should be multiplied not added.
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24 Apr 2006, 23:47
Alternatively,

P(!A) = 0.4
P(!B) = 0.5

P(!A AND !B) = 0.4 * 0.5 = 0.2
24 Apr 2006, 23:47
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