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The probability of pulling a black ball out of a glass jar

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The probability of pulling a black ball out of a glass jar [#permalink] New post 22 Sep 2007, 09:31
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).
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Re: combination_break it [#permalink] New post 22 Sep 2007, 09:55
IrinaOK wrote:
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).


I got b
P(black)=1/x
P(break and black)=1/y=P(black)xP(break)
P(break)= x/y
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Re: combination_break it [#permalink] New post 22 Sep 2007, 09:57
IrinaOK wrote:
The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).


A = probability of pulling a black ball out of a glass jar 1/X
B = probability of breaking the jar
C = pulling a black ball out of a glass jar and breaking the jar 1/Y

A * B = C

solve for B: B = C / A
B = (1/Y) / (1/X)
B = X /Y (answer B)
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 [#permalink] New post 22 Sep 2007, 10:05
i got B too...

prob of pulling ball 1/x

prob of breaking jar 1/n

prob of pulling ball AND breaking jar 1/y

1/x * 1/n =1/y

1/n=x/y
  [#permalink] 22 Sep 2007, 10:05
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