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The probability of Sam passing the exam is 1/4. The

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The probability of Sam passing the exam is 1/4. The [#permalink] New post 28 Jan 2006, 08:06
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The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/6.
What is the probability of Michael passing his driving test?

a) 1/24.
b) 1/2.
c) 1/3.
d) 2/3.
e) 2/5
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Re: PS - one more prob. [#permalink] New post 28 Jan 2006, 08:55
sperumba wrote:
The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/6.
What is the probability of Michael passing his driving test?

a) 1/24.
b) 1/2.
c) 1/3.
d) 2/3.
e) 2/5


P(S) = the probability of Sam passing the exam =1/4

P(M)= the probability of Michael passing the driving test=?

P(S) *P(M)= The probability of Sam passing the exam and Michael passing the driving test = 1/6

P(M) = (1/6)/(1/4) = 2/3
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 [#permalink] New post 28 Jan 2006, 09:53
2/3

Probability of A and B = probability of A * probability of B.
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 [#permalink] New post 28 Jan 2006, 18:01
Indicate A as the probability of Michael passing the driving test.
The probability of Sam passing the test is 1/4, the probability of both events happening together is 1/6 so: 1/4 x A = 1/6 therefore A = 2/3.
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 [#permalink] New post 28 Jan 2006, 20:45
P(michael pass) * P(sam pass) = 1/6
P(michael pass) = (1/6)/P(sam pass)
P(michael pass) = (1/6)/1/4 = 2/3

ANs D
  [#permalink] 28 Jan 2006, 20:45
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The probability of Sam passing the exam is 1/4. The

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