The product of three distinct integers, a, b, and c, is 252. If each

The question says that abc=252
As the integer is greater than 1, we can surely take the first integer as 2,which is the lowest one. To find out the greatest possible value i have to choose or find out as lowest as possible. 252 is even so i can take the 2 as the lowest value. So, the remaining value will be 126. Now i have to find out the second lowest possible value from 126. I can not take it as 2 because the integer must be distinctive to each other. So, i can take it as 3 because 3 is the factor of 126 (the summation of 126 separately is 9, which is divisible by 3), so the highest possible value is exactly 42, which is D.
Thank you...


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So 252 can be written as out of which the greatest possible value of the any of the three integers will be 42 * 3 * 2
2|252
2|126
3|63
3|21
7|7
|1

D