the rate of certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of the chemical B present. if the concentration of chemical B is increased by 100%, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged.
Let the rate of the reaction is r and concentration of chemical A is A and concentration of chemical B is B.
According to the question , r is proportional to A^2
and r is also proportional to 1/B
Combining these two condition , r =K (A^2/B) , where K is proportionality constant.
Now in the changed condition B has increased by 100 % means is has become 2B.
So for keeping the rate constant we have to change the concentration of A, from A to ((Square root of 2)*A)
As K (((square root of 2)A)^2)/2B = K (A^2/B) =r
Now, let after increase of x% ,A has become ((square root of 2)A) i.e 1.414*A
Answer is D.Please consider KUDOS if it helped u in some way.Thanks