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The rear wheels of a car crossed a certain line 0.5 second

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The rear wheels of a car crossed a certain line 0.5 second [#permalink] New post 14 Jul 2012, 00:53
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The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5280 feet = 1 mile)

A. (\frac{20}{5280})(\frac{60^2}{0.5})

B. (\frac{20}{5280})(\frac{60}{0.5})

C. (\frac{20}{5280})(\frac{0.5}{60^2})

D. \frac{(20)(5280)}{(60^2)(0.5)}

E. \frac{(20)(5280)}{(60)(0.5)}
[Reveal] Spoiler: OA

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Re: The rear wheels of a car crossed a certain line 0.5 second [#permalink] New post 14 Jul 2012, 01:57
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Stiv wrote:
The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5280 feet = 1 mile)

A. (\frac{20}{5280})(\frac{60^2}{0.5})
B. (\frac{20}{5280})(\frac{60}{0.5})
C. (\frac{20}{5280})(\frac{0.5}{60^2})
D. \frac{(20)(5280)}{(60^2)(0.5)}
E. \frac{(20)(5280)}{(60)(0.5)}


We need to find the speed of the car in miles per hour. So, we should convert feet in miles and seconds in hours.

20 feet is \frac{20}{5280} miles;
0.5 second is \frac{0.5}{3600}=\frac{0.5}{60^2} hours;

The speed of the car therefore is \frac{distance}{time}=\frac{(\frac{20}{5280})}{(\frac{0.5}{60^2})}=(\frac{20}{5280})*(\frac{60^2}{0.5}).

Answer: A.

Similar question to practice: a-train-traveling-at-a-constant-speed-down-a-straight-track-87124.html

Hope it helps.
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Re: The rear wheels of a car crossed a certain line 0.5 second [#permalink] New post 02 Jul 2013, 00:18
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

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Re: The rear wheels of a car crossed a certain line 0.5 second [#permalink] New post 02 Jul 2013, 00:18
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Other conversion problems to practice:
if-an-object-travels-100-feet-in-2-seconds-what-is-the-103364.html
the-rear-wheels-of-a-car-crossed-a-certain-line-0-5-second-135753.html
a-train-traveling-at-a-constant-speed-down-a-straight-track-87124.html
a-welder-received-an-order-to-make-a-1-million-liter-126154.html
a-car-traveling-at-a-certain-constant-speed-takes-2-seconds-126658.html
if-an-automobile-averaged-22-5-miles-per-gallon-of-gasoline-109083.html
if-1-kilometer-is-approximately-0-6-mile-which-of-the-140731.html
measuring-standards-conversion-106516.html
if-the-speed-of-x-meters-per-second-is-equivalent-to-the-127005.html
if-10-millimeters-equal-1-centimeter-how-many-square-48538.html
the-speed-of-light-is-approximately-149492.html

Hope it helps
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: The rear wheels of a car crossed a certain line 0.5 second [#permalink] New post 05 Aug 2013, 12:31
The rear wheels of a car crossed a certain line 0.5 second after the front wheels crossed the same line. If the centers of the front and rear wheels are 20 feet apart and the car traveled in a straight line at a constant speed, which of the following gives the speed of the car in miles per hour? (5280 feet = 1 mile)

The car traveled 20 feet in 1/2 second. This means it traveled 40 feet a second or 2400 feet/minute. This equates to .45 miles a minute or roughly 27 miles/hour.

20/5280 * (60^2) / .5
20/5280 * 3600/.5
20/5280 * 7200
300/11 = roughly 27

ANSWER: A
Re: The rear wheels of a car crossed a certain line 0.5 second   [#permalink] 05 Aug 2013, 12:31
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