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# The rectangle has fencing surrounding an animal pen 20

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Eternal Intern
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The rectangle has fencing surrounding an animal pen 20 [#permalink]  09 Jul 2003, 05:59
The rectangle has fencing surrounding an animal pen 20 meters by 5 meters. If an additional 4 square meters is to be enclosed by moving just one side of the pen, while retaining its rectangular shape, what is the least possible number of meters of additional fencing needed?
Eternal Intern
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Need picture [#permalink]  09 Jul 2003, 08:02
.4 is right, but why, helps to do a picture.
Manager
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[#permalink]  09 Jul 2003, 22:17
Why would it not be 1/5? When you look at the picture, the new area is discernable as (.4)(20) = 8. The question said additional area of 4, so why not 1/2 of .4 = .2?
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[#permalink]  10 Jul 2003, 02:32
JP wrote:
Why would it not be 1/5? When you look at the picture, the new area is discernable as (.4)(20) = 8. The question said additional area of 4, so why not 1/2 of .4 = .2?

2/5 (2*1\5) is the additional fencing needed. the new breadth is 5+1\5.
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[#permalink]  10 Jul 2003, 02:43
JP wrote:
Why would it not be 1/5? When you look at the picture, the new area is discernable as (.4)(20) = 8. The question said additional area of 4, so why not 1/2 of .4 = .2?

because both sides of the fence have to be increased and not one.
2*1/5=0.4
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[#permalink]  10 Jul 2003, 08:56
Expert's post
Sorry, i think I did a wrong picture

but I am just an artist
[#permalink] 10 Jul 2003, 08:56
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# The rectangle has fencing surrounding an animal pen 20

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