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The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 02:38
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Question Stats:
77% (02:20) correct
22% (01:01) wrong based on 6 sessions
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions ProjectThe sequence a_1, a_2, a_3, ... , a_n, ... is such that a_n=\frac{a_{n-1}+a_{n-2}}{2} for all n\geq{3}. If a_3 = 4 and a_5 = 20, what is the value of a_6 ? (A) 12 (B) 16 (C) 20 (D) 24 (E) 28 Diagnostic Test Question: 3 Page: 20 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Explanations (OE) to them along with an alternate approaches if necessary. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button (the best solution we'll be put along the OE in the second post); 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 02:39
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 05:58
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Hi, This one has be solved step by step, and there is chance of making mistakes. Difficulty level: 600 a_n=\frac{a_{n-1}+a_{n-2}}2or a_n is the average of last two terms, thus, \frac{a_3+a_4}2=a_5\frac{a_4+a_5}2=a_6Subtracting these equations; \frac{a_5-a_3}2=a_6-a_5a_6=\frac{3a_5-a_3}2=\frac{3*20-4}2=28Thus, Answer is (E). Regards,
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 06:11
a4=2*a6-a5;=>a4=40-4=36; therefore,a6=(36+20)/2=28;
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 20:27
a5 = (a3+a4) / 2 => a4 = 2(a5) - a3 = 2 x 20 - 4 = 36
a6 = (a4+a5) / 2 = (36 + 20) / 2 = 28
Option E is correct.
Difficulty level is 600.
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 21:00
Its E from the given formula we can deduce A4 and then take average of A4 and A5 and there is your answer
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 23:36
its E.
a5=(a4+a3)/2 substituting you get a4=36
now a6=(a5+a4)/2 substitute to get a6 as 28
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
14 Jun 2012, 23:47
I'm not sure how efficient my method was:
a3 = 4 = (a2 + a1) / 2 :. 8 = a2 + a1
a5 = 20 = (a4 + a3) / 2 :. 40 = a4 + a3 = a4 + 4 :. a4 = 36
a6 = ? a6 = (a5 + a4) / 2 a6 = (20 + 36) / 2 = 28
(E) 28
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
16 Jun 2012, 03:45
I consider it to be higher then 600 level due to function involved although very each one if one is able to decipher.
Calculate the value of a4 as a5 and a3 is given. Thus a5=a4+a3/2 20=(a4+4)/2 or 40-4=a4.
a6= 20+36/2= 28
Answer: E
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
22 Jun 2012, 02:38
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1 [#permalink]
19 Dec 2012, 22:38
a_3 = 4 a_4 = ? a_5 = 20 a_6 = ?
a_n=\frac{a_{n-1} + a_{n-2}}{2} 20(2)=\frac{4 + a_4}{2} 40=4 + a_4 36 = a_4
a_6 = \frac{20 + 36}{2}=28
Answer: (E) 28
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Re: The sequence a1, a2, a3, ... ,an, ... is such that an = an-1
[#permalink]
19 Dec 2012, 22:38
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