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The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
23 Mar 2009, 10:17

00:00

A

B

C

D

E

Difficulty:

25% (medium)

Question Stats:

68% (02:03) correct
32% (00:51) wrong based on 176 sessions

The sequence a_1, a_2, a_3, ... a_n of n integers is such that a_k=k if k is odd, and a_k=-a_{k-1} if k is even. Is the sum of the terms in the sequence positive?

Re: DS GMAT perp sequence [#permalink]
23 Mar 2009, 21:48

My Answer: D. EACH statement ALONE is sufficient.

Explanation:

As, ak=k if k is odd Hence, a1=1 a3=3, a5=5 etc.

And as ak=-ak-1 if k is even Hence, a2=-a1=-1 a4=-a3=-3 a6=-a5=-5 etc.

So, if n is even, a1+a2+....+an = a1+(-a1)+a3+(-a3)+....+an-1+(-an-1) = 0 All terms get canceled.

And if n is odd, a1+a2+....+an = a1+(-a1)+a3+(-a3)+....+an-2+(-an-2)+an = an As, ak=k if k is odd, an = n if n is odd Only an remains at the end, which is a positive number equal to n.

Re: The sequence a1, a2,a3,....an of n integers is such that [#permalink]
29 Dec 2012, 03:30

3

This post received KUDOS

Expert's post

KevinBrink wrote:

Can you explain this statement a little further, I just do not understand how you arrived at that statement Hence, a2=-a1=-1. Regards

Stem says that a_k=k if k is odd. So, for k=1=odd we have that a_1=1.

The sequence a_1, a_2, a_3, ... a_n of n integers is such that a_k=k if k is odd, and a_k=-a_{k-1} if k is even. Is the sum of the terms in the sequence positive?

We have following sequence: a_1=1; a_2=-a_1=-1; a_3=3; a_4=-a_3=-3; a_5=5; a_6=-a_5=-5; ...

Basically we have a sequence of positive and negative odd integers: 1, -1, 3, -3, 5, -5, 7., -7, 9, -9, ...

Notice than if the number of terms in the sequence (n) is odd then the sum of the terms will be positive, for example if n=3 then a_1+a_2+a_3=1+(-1)+3=3, but if the number of terms in the sequence (n) is even then the sum of the terms will be zero, for example if n=4 then a_1+a_2+a_3+a_4=1+(-1)+3+(-3)=0. Also notice that odd terms are positive and even terms are negative.

(1) n is odd --> as discussed the sum is positive. Sufficient. (2) a_n is positive --> n is odd, so the same as above. Sufficient.

Re: The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
30 Dec 2012, 04:13

Accountant wrote:

The sequence a_1, a_2, a_3, ... a_n of n integers is such that a_k=k if k is odd, and a_k=-a_{k-1} if k is even. Is the sum of the terms in the sequence positive?

(1) n is odd. (2) a_n is positive

In a sequence it always helps to observer a first few terms. Given these definitions : a1=1, a2=-a1 = -1, a3 = 3, a4=-a3 = -3

so it is clear consecutive terms from begining are canceling each other, i.e., 1-1+2-2+3-3 etc

Also, the sum is either positive in which case it is equal to the last odd term or it is zero.

So knowing either the term is odd or that last term was positive helps us know that sum of the terms are positive

Re: The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
03 Jan 2013, 21:38

2

This post received KUDOS

a1 + (-a1) + a3 + (-a3) + .......

1. n is odd --> last term is an which is positive every other term cancels out 2. an can be +ve only if n is odd which will be the last term same as above hence answer is D

Re: The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
14 Feb 2013, 04:55

Now this is what i dont understand. They just mention "k" (i guess constant) but k can take any value -1,-3 or +2. SHouldnt the answer be B then because the statement 2 specifically says that an is positive.

Re: The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
14 Feb 2013, 05:05

Expert's post

maddyboiler wrote:

Now this is what i dont understand. They just mention "k" (i guess constant) but k can take any value -1,-3 or +2. SHouldnt the answer be B then because the statement 2 specifically says that an is positive.

k in a_k is a subscript, meaning that a_k is k_{th} term in the given sequence which starts from a_1, thus k must be some positive integer.

Re: The sequence a1, a2, a3, ..., an of n integers is such that [#permalink]
14 Feb 2013, 09:17

1

This post received KUDOS

Expert's post

maddyboiler wrote:

Now this is what i dont understand. They just mention "k" (i guess constant) but k can take any value -1,-3 or +2. SHouldnt the answer be B then because the statement 2 specifically says that an is positive.

dont go into complex things. Just visualize the sequence

It can be 2 way

1,-1, 3,-3, 5,-5, 7,-7 ending in negative term The sum will be zero in this case

1,-1, 3,-3, 5,-5, 7 ending in positive term The sum will be the last term of sequence

we have asked is the sum positive ? ----------> is the sequence as per 2nd case ? ----------> is the a(n) odd ? or is the a(n) positive ? both the statements answer these questions so both are sufficient _________________

Re: The sequence a1, a2,a3,....an of n integers is such that [#permalink]
20 Nov 2013, 02:29

Bunuel wrote:

KevinBrink wrote:

Can you explain this statement a little further, I just do not understand how you arrived at that statement Hence, a2=-a1=-1. Regards

Stem says that a_k=k if k is odd. So, for k=1=odd we have that a_1=1.

The sequence a_1, a_2, a_3, ... a_n of n integers is such that a_k=k if k is odd, and a_k=-a_{k-1} if k is even. Is the sum of the terms in the sequence positive?

We have following sequence: a_1=1; a_2=-a_1=-1; a_3=3; a_4=-a_3=-3; a_5=5; a_6=-a_5=-5; ...

Basically we have a sequence of positive and negative odd integers: 1, -1, 3, -3, 5, -5, 7., -7, 9, -9, ...

Notice than if the number of terms in the sequence (n) is odd then the sum of the terms will be positive, for example if n=3 then a_1+a_2+a_3=1+(-1)+3=3, but if the number of terms in the sequence (n) is even then the sum of the terms will be zero, for example if n=4 then a_1+a_2+a_3+a_4=1+(-1)+3+(-3)=0. Also notice that odd terms are positive and even terms are negative.

(1) n is odd --> as discussed the sum is positive. Sufficient. (2) a_n is positive --> n is odd, so the same as above. Sufficient.

Answer: D.

Hope it's clear.

Thanks. But could a1 = -1? the question does not state that k>0 so I make a big mistake here... Please help to explain. Thanks a lot!

Re: The sequence a1, a2,a3,....an of n integers is such that [#permalink]
20 Nov 2013, 02:33

Expert's post

Cee0612 wrote:

Bunuel wrote:

KevinBrink wrote:

Can you explain this statement a little further, I just do not understand how you arrived at that statement Hence, a2=-a1=-1. Regards

Stem says that a_k=k if k is odd. So, for k=1=odd we have that a_1=1.

The sequence a_1, a_2, a_3, ... a_n of n integers is such that a_k=k if k is odd, and a_k=-a_{k-1} if k is even. Is the sum of the terms in the sequence positive?

We have following sequence: a_1=1; a_2=-a_1=-1; a_3=3; a_4=-a_3=-3; a_5=5; a_6=-a_5=-5; ...

Basically we have a sequence of positive and negative odd integers: 1, -1, 3, -3, 5, -5, 7., -7, 9, -9, ...

Notice than if the number of terms in the sequence (n) is odd then the sum of the terms will be positive, for example if n=3 then a_1+a_2+a_3=1+(-1)+3=3, but if the number of terms in the sequence (n) is even then the sum of the terms will be zero, for example if n=4 then a_1+a_2+a_3+a_4=1+(-1)+3+(-3)=0. Also notice that odd terms are positive and even terms are negative.

(1) n is odd --> as discussed the sum is positive. Sufficient. (2) a_n is positive --> n is odd, so the same as above. Sufficient.

Answer: D.

Hope it's clear.

Thanks. But could a1 = -1? the question does not state that k>0 so I make a big mistake here... Please help to explain. Thanks a lot!

We are told that a_k=k if k is odd. Now, substitute k=1 and see what you get. _________________

I attended a portfolio workshop hosted by Business Design club today. Competing against thousands of MBA students with the entire world, you need more than your resume and coverletter...

so actually alongside the MBA studies, I am studying for personal trainer exam in December as a side. I can basically only read when I’m in the subway...