The sides of a parallelogram are 6 and 8, respectively. : Quant Question Archive [LOCKED]
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# The sides of a parallelogram are 6 and 8, respectively.

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VP
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The sides of a parallelogram are 6 and 8, respectively. [#permalink]

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27 Jun 2008, 02:45
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The sides of a parallelogram are 6 and 8, respectively. Which of the following could be the area of the parallelogram?
I. 12
II. 24
III. 48
(A) I only
(B) II only
(C) III only
(D) I and II
(E) I, II, and III
SVP
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Re: area of a parallelogram [#permalink]

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27 Jun 2008, 03:02
I think the answer is E.

If parallelogram is a rectangle, then the area will be 48.

for other cases, if the height of the parallelogram is 2 or 4 then the resulting base could be more than 6.
Intern
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Re: area of a parallelogram [#permalink]

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05 Jul 2008, 07:34
S = Base * Height

The answer is I & II. The A cannot be equal to the product of the two sides 48 (6*8)
VP
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Re: area of a parallelogram [#permalink]

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05 Jul 2008, 08:24
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GMAT Tutor
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Re: area of a parallelogram [#permalink]

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05 Jul 2008, 09:57
Rectangles are parallelograms. 48 is also possible for the area.
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Re: area of a parallelogram [#permalink]

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05 Jul 2008, 11:02
IanStewart wrote:
Rectangles are parallelograms. 48 is also possible for the area.

another E and for same reason.
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Re: area of a parallelogram [#permalink]

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07 Jul 2008, 00:32
another E..

reasoning is well explained by previous posters

Re: area of a parallelogram   [#permalink] 07 Jul 2008, 00:32
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