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# The sides of right triangle ABC are such that the length of

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The sides of right triangle ABC are such that the length of [#permalink]  12 Mar 2013, 04:13
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The sides of right triangle ABC are such that the length of side AB is greater than the length of side BC, which itself is greater than the length of side AC. If side AB = 143 and side AC = 55, what is the area of the triangle?

A. 3113
B. 3224
C. 3432
D. 3630
E. 7260
[Reveal] Spoiler: OA

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Last edited by Bunuel on 12 Mar 2013, 04:21, edited 1 time in total.
Edited the question.
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Re: The sides of right triangle ABC are such that the length of [#permalink]  12 Mar 2013, 04:29
Expert's post
emmak wrote:
The sides of right triangle ABC are such that the length of side AB is greater than the length of side BC, which itself is greater than the length of side AC. If side AB = 143 and side AC = 55, what is the area of the triangle?

A. 3113
B. 3224
C. 3432
D. 3630
E. 7260

Given that AB>BC>AC. So, AB is the hypotenuse of the triangle.

$$BC=\sqrt{143^2-55^2}=\sqrt{(11*13)^2-(11*5)^2}=11\sqrt{13^2-5^2}=11*12$$.

The area = 1/2*BC*AC = 1/2*(11*12)*55 = 66*55 = 3630.

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Re: The sides of right triangle ABC are such that the length of [#permalink]  21 Oct 2014, 14:51
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Re: The sides of right triangle ABC are such that the length of   [#permalink] 21 Oct 2014, 14:51
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# The sides of right triangle ABC are such that the length of

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