mmcooley33 wrote:

The Simplastic language has only 2 unique values and 3 unique consonants. Every noun in Simplastic has the structure CVCVC, where C stands for a consonant and V stands for a vowel. How many different nouns are possible in Simplastic?

a.9

b.12

c.36

d.72

e.108

mmcooley33 wrote:

The answer is E because order does not matter making the combination 3*2*3*2*3?

The nouns have

fixed structure C-V-C-V-C. Now,

each C can take 3 values (let's say X, Y or Z) and

each V can take 2 values (let's say A or E), so there will be 3*2*3*2*3=108 nouns possible.

Answer: E.

It's basically the same if it were how many different 5-digit numbers are possible with the following structure odd-even-odd-even-odd, where odd numbers can be only 1, 3 or 5 and even numbers only 2 and 4.

adhithya wrote:

108 is the answer if we assume that repetition is allowed, but how do we know whether repn is allowed or not if question doesnt mention anything

It's natural to think that a noun can have for example two same vowels (X-A-Y-A-Z) or 3 same consonants (X-A-X-A-X), so if this was not the case then this would be explicitly mentioned.

Great questions, at one point when this situation will arise, wouldn't we divide it by -