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The six fair dice are rolled together. What is the

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New post 08 Feb 2006, 11:28
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The six fair dice are rolled together. What is the probability of having Poker (1-2-3-4-5-6) in all the possible combinations?
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New post 08 Feb 2006, 13:07
5/216

6/6 * 5/6 * 4/6 * 3/6 * 2/6 * 1/6 = 5/216

OA pls.

EDIT: my calculations were wrong, it should be 5/324.

Last edited by arichards728 on 09 Feb 2006, 10:38, edited 1 time in total.
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New post 08 Feb 2006, 15:28
same as arichards.
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New post 08 Feb 2006, 15:46
6! / (6^6) = arichards answer
but I think you had a problem with your simplification cause I got 5/324 not 5/216
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New post 08 Feb 2006, 18:21
where's the question from?
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New post 08 Feb 2006, 18:48
# of ways to rotate 1-6 = 6! = 720
total # of possibilities = 6^6

probability = 5/324
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New post 09 Feb 2006, 06:35
1/216

1 * 5/6 * 4/6 * 3/6 * 2/6 * 1/6 = 1/216

I am not sure how did the person before do the same calculations and come up with 5/216?
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New post 09 Feb 2006, 10:13
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New post 11 Feb 2006, 05:07
i am lost :cry: i dont know how to play poker.. didnt know how to solve. some one pls explain
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New post 11 Feb 2006, 13:14
razrulz wrote:
i am lost :cry: i dont know how to play poker.. didnt know how to solve. some one pls explain


Is not about poker, the same question could be:

rolled a dice six times (or six dice one time) what is the probability that each of the six numbers 1-2-3-4-5-6 (faces) appears
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New post 11 Feb 2006, 20:21
conocieur wrote:
razrulz wrote:
i am lost :cry: i dont know how to play poker.. didnt know how to solve. some one pls explain


Is not about poker, the same question could be:

rolled a dice six times (or six dice one time) what is the probability that each of the six numbers 1-2-3-4-5-6 (faces) appears


mmm ok cono, sorry for bein naive, but can u temme y 6!/6^6 ? pls
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New post 12 Feb 2006, 19:49
razrulz wrote:
conocieur wrote:
razrulz wrote:
i am lost :cry: i dont know how to play poker.. didnt know how to solve. some one pls explain


Is not about poker, the same question could be:

rolled a dice six times (or six dice one time) what is the probability that each of the six numbers 1-2-3-4-5-6 (faces) appears


mmm ok cono, sorry for bein naive, but can u temme y 6!/6^6 ? pls


I think it has been explained already in the other answers but I will try to make it clear

6! = 6 * 5 * 4 * 3 * 2 * 1
6^6 = 6 * 6 * 6 * 6 * 6 * 6

so: 6! / 6^6 = 6/6 * 5/6 * 4/6 * 3/6 * 2/6 * 1/6
  [#permalink] 12 Feb 2006, 19:49
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