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the statement is: Is r^5 > s^r

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the statement is: Is r^5 > s^r [#permalink] New post 03 Jan 2007, 22:26
the statement is: Is r^5 > s^r
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 [#permalink] New post 04 Jan 2007, 00:48
(C) for me also :)

From (1)
o If r=s=1, then r^5 = s^r = 1
o If r=1 s=-1, then r^5=1 > (-1)^1 = -1

INSUFF.

From (2)
No information about r.

INSUFF.

(1) combined with (2)
r = s^4 = 16

We know r and s, so we can conlude.

SUFF.
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 [#permalink] New post 04 Jan 2007, 04:28
Taking logs on both sides

we need to find

5*logr > r*logs

logr/logs > r/5-----------(a)

but from (1) we have r = s^4

so substitute in (a)

4 > s^4/5

so 4> 16/5 (we know s=-2 from II)

so C
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 [#permalink] New post 04 Jan 2007, 06:29
You all got C, I had gotten C too, but the OA and OE is something else
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 [#permalink] New post 04 Jan 2007, 06:58
jainan24 wrote:
You all got C, I had gotten C too, but the OA and OE is something else


And what about this case : If s=-1, then r=1 and r^5=1 > (-1)^1 = -1 ? :)

From what I read, it is explained that (-1)^((-1)^4) = 1.... that's not true :)..... a^1 = a not |a|.

What is the source of this surprising question? :)
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 [#permalink] New post 04 Jan 2007, 11:07
jainan24 wrote:
McGrawhill GMAT


Thanks.

I have never heard about it before :).... The OA & OE are wrong :)
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 [#permalink] New post 04 Jan 2007, 14:24
You guys are right. It´s C.
  [#permalink] 04 Jan 2007, 14:24
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the statement is: Is r^5 > s^r

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