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The sum of the integers in list S is the same as the sum of

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The sum of the integers in list S is the same as the sum of [#permalink] New post 28 Dec 2007, 09:12
The sum of the integers in list S is the same as the sum of the integers in list T. Does S contains more integers than T?

1. the average of the integers in S is less than the average of the integers in T
2. the median of the integers in S is greater than the median of the integers in T
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 [#permalink] New post 28 Dec 2007, 09:18
all integers in S added together = all integers in T added together

1. if the average in S is less than the average in T then S must have more integers. It's the only way they could be equal.

2. median doesn't tell us anything.

S could be 5, 10, 15 (with a median of 10) and T could be 5, 9, 1,000,000 (with a median of 9) or S could be 9,10,25 and T could be 8,9,10. Median on it's own doesn't tell us anything useful.

Answer A
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Re: median [#permalink] New post 28 Dec 2007, 09:21
marcodonzelli wrote:
The sum of the integers in list S is the same as the sum of the integers in list T. Does S contains more integers than T?

1. the average of the integers in S is less than the average of the integers in T
2. the median of the integers in S is greater than the median of the integers in T


Say sum is 20

Using (1) 20/N <20/N1 so list s has more numbers (SUFF)


Using (2)
Lets s have 2 2 2 14
Let T have 1 1 1 17 (insuff)
or s 2 2 2 14
T 1 1 18 ( may be T ( insuff

Answer (A)

Last edited by Damager on 28 Dec 2007, 09:35, edited 1 time in total.
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Re: median [#permalink] New post 28 Dec 2007, 10:22
marcodonzelli wrote:
The sum of the integers in list S is the same as the sum of the integers in list T. Does S contains more integers than T?

1. the average of the integers in S is less than the average of the integers in T
2. the median of the integers in S is greater than the median of the integers in T


Suppose the sum of the integers in S is equal to the sum of the integers in T, which we can call n.
If (1) is true, S contains fewer integers than T if n is negative and more if n is positive. I don't see why (1) is sufficient
Re: median   [#permalink] 28 Dec 2007, 10:22
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