marcodonzelli wrote:

The sum of the integers in list S is the same as the sum of the integers in list T. Does S contains more integers than T?

1. the average of the integers in S is less than the average of the integers in T

2. the median of the integers in S is greater than the median of the integers in T

Suppose the sum of the integers in S is equal to the sum of the integers in T, which we can call n.

If (1) is true, S contains fewer integers than T if n is negative and more if n is positive. I don't see why (1) is sufficient