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the sum of the intergers between 40 and 60?

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Manager
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the sum of the intergers between 40 and 60? [#permalink] New post 05 Oct 2009, 16:52
Hi,

how can i find the sum of integers between 40 & 60?

thanks,
Manager
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Re: the sum of the intergers between 40 and 60? [#permalink] New post 05 Oct 2009, 17:36
if its all inclusive 40 and 60, it is equal to the median * the numbers between 40 and 60 inclunsive so 50*21 =1050
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Re: the sum of the intergers between 40 and 60? [#permalink] New post 05 Oct 2009, 18:59
Good tech sfeiner!!

A more generic way to do it would be using the sum of an arithmetic progression -

n/2(2a +(n-1)*d)

where n is the total elements in the progression = 21
a = first term in the prog = 40
d = common difference in the Prog = 1

Applying to the formula 21/2(80+20) = 1050.
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Re: the sum of the intergers between 40 and 60? [#permalink] New post 06 Oct 2009, 01:40
Also...

sum=n(a+z)/2
where
n = number of terms
a = first term
z = last term

Applying here

Sum = 21(40+60)/2 = 1050
Re: the sum of the intergers between 40 and 60?   [#permalink] 06 Oct 2009, 01:40
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the sum of the intergers between 40 and 60?

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