the surface area of s snow shovel's blade : Integrated Reasoning (IR)
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the surface area of s snow shovel's blade

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the surface area of s snow shovel's blade [#permalink]

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New post 05 Jan 2014, 10:00
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Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?
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Last edited by LalaB on 23 Jan 2014, 10:27, edited 1 time in total.
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Re: the surface area of s snow shovel's blade [#permalink]

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New post 09 Jan 2014, 11:40
LalaB wrote:
Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?

Dear Lala B,
I would be happy to help. Question #2 of what??
Mike :-)
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Re: the surface area of s snow shovel's blade [#permalink]

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New post 23 Jan 2014, 10:29
sorry. forgot to attach the file
now everything should be ok

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Re: the surface area of s snow shovel's blade [#permalink]

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LalaB wrote:
Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?

OK, now that I have a diagram, it makes perfect sense and I am happy to help. :-)

First of all, here is a blog article on "trend lines", also as known as "best fit lines" or, more, formally, "least-square linear regression lines."
http://magoosh.com/gmat/2012/gmat-integ ... tterplots/

On that diagram, let's start simple. The line moves to the right two "grids" for every one "grid" it goes down. In other words, it moves to the right one "grid" for every half "grid" it goes down. So we could say that the slope is
slope = - (one vertical grid)/(two horizontal grids)
Now, what do these grids mean? The vertical axis is measured in hours to fatigue, and each grid, from one horizontal gray line to the next, is 0.2 hours, so half the distance between two adjacent horizontal gray lines is 0.1 hour. That's what Question #2 wants, a 0.1 hour decrease in time to fatigue. Well, in the space it takes for the line to drop half the distance between two adjacent horizontal gray lines, it goes the full distance between two vertical gray lines. The horizontal scale is area, measured in (cm)^2. Notice that the distance between two adjacent vertical gray lines is 200 (cm)^2. That's why, if we cross the entire distance between two adjacent vertical gray lines while dropping half the distance between two adjacent horizontal gray lines, we go down 0.1 hrs vertically and go up 200 (cm)^2 horizontally.

Does all this make sense?
Mike :-)
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Re: the surface area of s snow shovel's blade [#permalink]

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New post 05 Apr 2015, 08:42
Thank you mikemcgarry for the great explanation. I see where I went wrong.
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Re: the surface area of s snow shovel's blade [#permalink]

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New post 30 Sep 2016, 21:01
Hi.
Could you please explain the first part of the question too?
" the data point for which the distance to the trendline is greatest corresponds to a shovel blade surface area that is approximately ____?

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Re: the surface area of s snow shovel's blade [#permalink]

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New post 02 Oct 2016, 07:06
shagunbanthia wrote:
Hi.
Could you please explain the first part of the question too?
" the data point for which the distance to the trendline is greatest corresponds to a shovel blade surface area that is approximately ____?


The area to the trend line is the perpendicular distance (read shortest way to reach trend line) from the point.
As we can see all the points are very close to the line, almost touching except for the points at x= 8, and x = 10.
Clearly just by looking point at x = 8 if farthest from the line.
Re: the surface area of s snow shovel's blade   [#permalink] 02 Oct 2016, 07:06
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