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the surface area of s snow shovel's blade

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Current Student
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Joined: 23 Oct 2010
Posts: 387
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Followers: 14

Kudos [?]: 160 [0], given: 73

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the surface area of s snow shovel's blade [#permalink] New post 05 Jan 2014, 10:00
Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?
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Last edited by LalaB on 23 Jan 2014, 10:27, edited 1 time in total.
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Magoosh GMAT Instructor
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Re: the surface area of s snow shovel's blade [#permalink] New post 09 Jan 2014, 11:40
Expert's post
LalaB wrote:
Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?

Dear Lala B,
I would be happy to help. Question #2 of what??
Mike :-)
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Mike McGarry
Magoosh Test Prep

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Current Student
User avatar
Joined: 23 Oct 2010
Posts: 387
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Followers: 14

Kudos [?]: 160 [0], given: 73

GMAT ToolKit User
Re: the surface area of s snow shovel's blade [#permalink] New post 23 Jan 2014, 10:29
sorry. forgot to attach the file
now everything should be ok

Source- Gmatprep
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_________________

Happy are those who dream dreams and are ready to pay the price to make them come true

Expert Post
2 KUDOS received
Magoosh GMAT Instructor
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Joined: 28 Dec 2011
Posts: 2189
Followers: 607

Kudos [?]: 2451 [2] , given: 33

Re: the surface area of s snow shovel's blade [#permalink] New post 23 Jan 2014, 12:16
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Expert's post
LalaB wrote:
Here I cant get the answer to the question 2
I thought that 0.1 decrease is equal to 100 increase(at least visually). why 200?

OK, now that I have a diagram, it makes perfect sense and I am happy to help. :-)

First of all, here is a blog article on "trend lines", also as known as "best fit lines" or, more, formally, "least-square linear regression lines."
http://magoosh.com/gmat/2012/gmat-integ ... tterplots/

On that diagram, let's start simple. The line moves to the right two "grids" for every one "grid" it goes down. In other words, it moves to the right one "grid" for every half "grid" it goes down. So we could say that the slope is
slope = - (one vertical grid)/(two horizontal grids)
Now, what do these grids mean? The vertical axis is measured in hours to fatigue, and each grid, from one horizontal gray line to the next, is 0.2 hours, so half the distance between two adjacent horizontal gray lines is 0.1 hour. That's what Question #2 wants, a 0.1 hour decrease in time to fatigue. Well, in the space it takes for the line to drop half the distance between two adjacent horizontal gray lines, it goes the full distance between two vertical gray lines. The horizontal scale is area, measured in (cm)^2. Notice that the distance between two adjacent vertical gray lines is 200 (cm)^2. That's why, if we cross the entire distance between two adjacent vertical gray lines while dropping half the distance between two adjacent horizontal gray lines, we go down 0.1 hrs vertically and go up 200 (cm)^2 horizontally.

Does all this make sense?
Mike :-)
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Mike McGarry
Magoosh Test Prep

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Re: the surface area of s snow shovel's blade   [#permalink] 23 Jan 2014, 12:16
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