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Re: Equations & Solutions [#permalink]
15 Nov 2007, 13:52

yogachgolf wrote:

yogachgolf wrote:

x-y = 3 2x= 2y+6

The system of equations above has how many solutions?

(A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many

I thought it's A as well. But OA is E?

I see your point ... A + B can be an infinite number of things... I suppose we answered it on the basis that the two solutions given gave us no CERTAIN solutions...

I think the question is a touch ambiguous, but I suppose we could have read it more closely.

Re: Equations & Solutions [#permalink]
15 Nov 2007, 14:19

alrussell wrote:

yogachgolf wrote:

yogachgolf wrote:

x-y = 3 2x= 2y+6

The system of equations above has how many solutions?

(A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many

I thought it's A as well. But OA is E?

I see your point ... A + B can be an infinite number of things... I suppose we answered it on the basis that the two solutions given gave us no CERTAIN solutions...

I think the question is a touch ambiguous, but I suppose we could have read it more closely.

seems ok but we cannot solve the equations do not provide any value for x and y.

Any single linear equation with more than 1 variable in it has infinite solutions (provided no constraints are given).

Edit: I do not see any ambiguity in the question.

The number of solutions for a linear equation is the number of possible values the variables can have so as to satisfy the equation. There are infinite possible values for the variables x & y in the given equation and therefore there are infinite solutions.

Re: System of Equations [#permalink]
04 Apr 2011, 03:57

3

This post received KUDOS

petrifiedbutstanding wrote:

Attachment:

1.JPG

The system of equations above has how many solutions? (A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many

Sol:

\(x-y=3\) is same as \(2x=2y+6\)

\(2x=2y+6\) Dividing both sides by 2; \(x=y+3\) Subtracting y from both sides; \(x-y=3\)

Thus, we have only one equation: \(x-y=3\) This has infinitely many solutions such as: x=3,y=0 x=100,y=97 x=-100,y=-103 x=0.001, y=-2.999 x=1, y=-2 _________________

Any single linear equation with more than 1 variable in it has infinite solutions (provided no constraints are given).

Edit: I do not see any ambiguity in the question.

The number of solutions for a linear equation is the number of possible values the variables can have so as to satisfy the equation. There are infinite possible values for the variables x & y in the given equation and therefore there are infinite solutions.

Re: The system of equations above has how many solutions? [#permalink]
22 Aug 2015, 05:19

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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