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Re: Equations & Solutions [#permalink]
15 Nov 2007, 13:52
yogachgolf wrote:
yogachgolf wrote:
x-y = 3 2x= 2y+6
The system of equations above has how many solutions?
(A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many
I thought it's A as well. But OA is E?
I see your point ... A + B can be an infinite number of things... I suppose we answered it on the basis that the two solutions given gave us no CERTAIN solutions...
I think the question is a touch ambiguous, but I suppose we could have read it more closely.
Re: Equations & Solutions [#permalink]
15 Nov 2007, 14:19
alrussell wrote:
yogachgolf wrote:
yogachgolf wrote:
x-y = 3 2x= 2y+6
The system of equations above has how many solutions?
(A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many
I thought it's A as well. But OA is E?
I see your point ... A + B can be an infinite number of things... I suppose we answered it on the basis that the two solutions given gave us no CERTAIN solutions...
I think the question is a touch ambiguous, but I suppose we could have read it more closely.
seems ok but we cannot solve the equations do not provide any value for x and y.
Any single linear equation with more than 1 variable in it has infinite solutions (provided no constraints are given).
Edit: I do not see any ambiguity in the question.
The number of solutions for a linear equation is the number of possible values the variables can have so as to satisfy the equation. There are infinite possible values for the variables x & y in the given equation and therefore there are infinite solutions.
Re: System of Equations [#permalink]
04 Apr 2011, 03:57
3
This post received KUDOS
petrifiedbutstanding wrote:
Attachment:
1.JPG
The system of equations above has how many solutions? (A) None (B) Exactly one (C) Exactly two (D) Exactly three (E) Infinitely many
Sol:
\(x-y=3\) is same as \(2x=2y+6\)
\(2x=2y+6\) Dividing both sides by 2; \(x=y+3\) Subtracting y from both sides; \(x-y=3\)
Thus, we have only one equation: \(x-y=3\) This has infinitely many solutions such as: x=3,y=0 x=100,y=97 x=-100,y=-103 x=0.001, y=-2.999 x=1, y=-2 _________________
Any single linear equation with more than 1 variable in it has infinite solutions (provided no constraints are given).
Edit: I do not see any ambiguity in the question.
The number of solutions for a linear equation is the number of possible values the variables can have so as to satisfy the equation. There are infinite possible values for the variables x & y in the given equation and therefore there are infinite solutions.
Re: The system of equations above has how many solutions? [#permalink]
22 Aug 2015, 05:19
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