stne wrote:

we are asked to find the median of the 73 scores, which is the 37th term.

Now if we arrange the number of scores( not score intervals ) in ascending order as shown below which is what we do when we want to calculate the median of a number of terms:the Median term 37th falls in the 90-99 interval.

Confused as to , why we shouldn't arrange the frequency ( no. of scores in a particular interval ) in ascending order when calculating the Median.

50-59-------------------------- 2

60-69--------------------------10

70-79--------------------------16

90-99--------------------------18

80-89--------------------------27

Hi Stne,

To find

median of test-scores,we have to arrange them in an order (ascending or descending) and find the middle term.Now,the middle term is 37 th term in the order.

For the score distribution ,one can add one more column Cumulative frequency

SCORE INTERVAL---------NUMBER OF SCORES ---------

Cumulative Frequency50-59-------------------------- 2----------------------------- 2

60-69--------------------------10---------------------------- 12

70-79--------------------------16-----------------------------

2880-89--------------------------

27-----------------------------55

90-99--------------------------18-----------------------------

73We can see arranging the scores in ascending, shows

first 28 test scores are below 80.

Next 27 scores , i.e. 29th,30th,....,

37th,......,55th score appear in SCORE INTERVAL 80-89.

So median is in interval 80-89.

Hope it helps.

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