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# The total # of prime factors of the product

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Senior Manager
Joined: 30 Aug 2003
Posts: 330
Location: BACARDIVILLE
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The total # of prime factors of the product [#permalink]  09 Jan 2004, 14:33
The total # of prime factors of the product (8)^23*(21)^19*(13)^15 is?

a.118
b.119
c.4
d.57

***Any ideas on how to crack this one?
_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

Manager
Joined: 26 Dec 2003
Posts: 227
Location: India
Followers: 1

Kudos [?]: 2 [0], given: 0

but I got 122 as the total number of prime factors

8^23 can be written as (2^3)*23= 2^69, so 69 as prime factor

21^19 can be written as(3*7)^19=3^19 and 7^19, so 19+19

13^15 = 15 so total number =69+19+19+15=122
Senior Manager
Joined: 22 May 2003
Posts: 334
Location: Uruguay
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Kudos [?]: 33 [0], given: 0

I got the same as Rakesh did... 122

I guess it would be 4 if the question asked for the number of "different" prime factors.

But 122 is not among the choices... so... what should we do?
Senior Manager
Joined: 30 Aug 2003
Posts: 330
Location: BACARDIVILLE
Followers: 1

Kudos [?]: 1 [0], given: 0

_________________

Pls include reasoning along with all answer posts.
****GMAT Loco****
Este examen me conduce jodiendo loco

Manager
Joined: 26 Dec 2003
Posts: 227
Location: India
Followers: 1

Kudos [?]: 2 [0], given: 0

oh god 119 then is there any way to do it
Director
Joined: 13 Nov 2003
Posts: 971
Location: Florida
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Kudos [?]: 31 [0], given: 0

sunniboy007 wrote:

i stand stupid
i considered different prime factors i was thinking too much
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