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# The total price of n (n > 1) equally priced copies of a

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The total price of n (n > 1) equally priced copies of a [#permalink]  30 Nov 2008, 18:17
The total price of n (n > 1) equally priced copies of a certain book is $50. In terms of n, which of the following gives the total price of n - 1 of these copies? A) 50(n-1) B) 50/(n-1) C) {50(n-1)} / n D) 50n/(n-1) E) 50/{n(n-1)} I'm confused by the wording of this problem. My answer was B but its wrong. Any help is appreciated! Also, is it better to pick numbers or solve with variable for such problems? Thanks in advance! SVP Joined: 30 Apr 2008 Posts: 1893 Location: Oklahoma City Schools: Hard Knocks Followers: 26 Kudos [?]: 391 [1] , given: 32 Re: Total price of n-1 copies [#permalink] 30 Nov 2008, 18:58 1 This post received KUDOS I believe the answer is C The wording can be a bit confusing. It took me a few seconds to realize (n>1) is just telling us that n is greater than 1 and is not part of the actual problem. To break it down we need to know how much 1 book costs, and then multiply it by the new number of books. The new number of books is represented by n-1. so if the total of n books is$50, then 1 book is the total divded by the number of books summed to get that total, or 50 /n

Now we take the price of 1 (represented by 50/n) and multiply that by the new quantity of books n-1.

\frac{50}{n}* n-1 This is the same as \frac{50(n-1)}{n} or Answer C

nikki25 wrote:
The total price of n (n > 1) equally priced copies of a certain book is $50. In terms of n, which of the following gives the total price of n - 1 of these copies? A) 50(n-1) B) 50/(n-1) C) {50(n-1)} / n D) 50n/(n-1) E) 50/{n(n-1)} I'm confused by the wording of this problem. My answer was B but its wrong. Any help is appreciated! Also, is it better to pick numbers or solve with variable for such problems? Thanks in advance! _________________ ------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$. Director Joined: 14 Aug 2007 Posts: 739 Followers: 7 Kudos [?]: 77 [1] , given: 0 Re: Total price of n-1 copies [#permalink] 30 Nov 2008, 19:13 1 This post received KUDOS C it is. n books = 50$, 1 book = 50/n $=> n-1 books will cost= 50*(n-1)/n Re: Total price of n-1 copies [#permalink] 30 Nov 2008, 19:13 Similar topics Replies Last post Similar Topics: If n>1, is n equal to 2? (1) n has exactly 2 positive 3 11 Nov 2006, 08:50 If n is not equal to 0, is |n| < 4 ? (1) n^2 > 16 (2) 1 17 Feb 2008, 00:35 1 if the total price for n copies of a book is$31.5, what is 2 14 Jul 2008, 10:00
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