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The two legs of a right triangle are a and a - d, and the

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New post 05 Jun 2003, 19:16
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The two legs of a right triangle are a and a - d, and the hypotenuse is a + d. In terms of a, what is the value of d?

Just do the math, you don't need to know the answer. Please help out though.
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New post 05 Jun 2003, 19:56
here it is, VTay25

a^2 + (a-d)^2 = (a+d)^2

d = a/4

hope it helps
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New post 05 Jun 2003, 20:11
Expert's post
rommer wrote:
here it is, VTay25

a^2 + (a-d)^2 = (a+d)^2

d = a/4

hope it helps



so we get: a^2+ a^2-2ad+d^2 = a^2+2ad+d^2

we get a^2=4ad or a = 4d or d=a/4

Hm... not really impossible :wink:
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New post 05 Jun 2003, 21:01
I also got a/4

my way is

1. ---pick the number 3, 4, 5 each of which is the side of a right triangle.

2. ---a= 4, a-d= 3 thus a+d = 5

3. --- that mean d=1

4. --- the relationship between a and d is a/4 = d
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New post 14 Mar 2006, 20:12
kewl....just when i was thinking abt factors etc etc, so much simpler to pic nos...
  [#permalink] 14 Mar 2006, 20:12
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