bmwhype2 wrote:

The useful life of a certain piece of equipment is determined by the following formula: u =(8d)/h2, where u is the useful life of the equipment, in years, d is the density of the underlying material, in g/cm3, and h is the number of hours of daily usage of the equipment. If the density of the underlying material is doubled and the daily usage of the equipment is halved, what will be the percentage increase in the useful life of the equipment?

300%

400%

600%

700%

800%

I am assuming your question is u =(8d)/h

^2,

Hence new equation would be

\(u_1 = \frac{8 * (2d)}{(\frac{h}{2})^2}\) --> \(u_1 = 8 * \frac{8 * d} {({h})^2}\) --> \(u_1 = 8*u\)

Hence 700% increase....

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