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The value of (2^-14)+(2^-15)+(2^-16) + (2^-17) is how times the value of 2^-17?

A. 3/2

B. 5/2

C. 3

D. 4

E. 5

Original question reads: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is how many times the value of 2^(-17)?

We need to find the value of: \(\frac{\frac{1}{5}*(2^{-14}+2^{-15}+2^{-16}+2^{-17})}{ 2^{-17}}=\frac{\frac{1}{5}*(\frac{1}{2^{14}}+\frac{1}{2^{15}}+\frac{1}{2^{16}}+\frac{1}{2^{17}})}{\frac{1}{2^{17}}}\).

Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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15 Apr 2012, 06:47

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if you take 2^(-17) common in the numerator, you will have 2^(-17) { 8 + 4 + 2 + 1} which equals 15. This 15 cancels with 5 in the denominator and leaves {3} 2^-(17). Slightly quicker this way i feel.

Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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09 Oct 2013, 19:41

Bunuel wrote:

andih wrote:

The value of (2^-14)+(2^-15)+(2^-16) + (2^-17) is how times the value of 2^-17?

A. 3/2

B. 5/2

C. 3

D. 4

E. 5

Original question reads: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is how many times the value of 2^(-17)?

We need to find the value of: \(\frac{\frac{1}{5}*(2^{-14}+2^{-15}+2^{-16}+2^{-17})}{ 2^{-17}}=\frac{\frac{1}{5}*(\frac{1}{2^{14}}+\frac{1}{2^{15}}+\frac{1}{2^{16}}+\frac{1}{2^{17}})}{\frac{1}{2^{17}}}\).

Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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09 Oct 2013, 20:15

runningguy wrote:

Bunuel wrote:

andih wrote:

The value of (2^-14)+(2^-15)+(2^-16) + (2^-17) is how times the value of 2^-17?

A. 3/2

B. 5/2

C. 3

D. 4

E. 5

Original question reads: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is how many times the value of 2^(-17)?

We need to find the value of: \(\frac{\frac{1}{5}*(2^{-14}+2^{-15}+2^{-16}+2^{-17})}{ 2^{-17}}=\frac{\frac{1}{5}*(\frac{1}{2^{14}}+\frac{1}{2^{15}}+\frac{1}{2^{16}}+\frac{1}{2^{17}})}{\frac{1}{2^{17}}}\).

Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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16 May 2016, 22:25

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Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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19 Jul 2016, 12:13

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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21 Jul 2016, 09:41

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carollu wrote:

The value of \(\frac{2^{(-14)} + 2^{(-15)} + 2^{(-16)} + 2^{(-17)}}{5}\) is how many times the value of \(2^{(-17)}\)?

A. 3/2 B. 5/2 C. 3 D. 4 E. 5

We start by translating the question. We are asked (2^-14) + (2^-15) + (2^-16) + (2^-17) is how times the value of 2^-17. We can express it as the following:

The answer is C.
_________________

Jeffrey Miller Scott Woodbury-Stewart Founder and CEO

Re: The value of (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is [#permalink]

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22 Aug 2016, 14:15

I think we can solve it another way. please expert correct me if I am wrong. 2^(-17)* (2^3+2^2+2^1+1)/5 = 2^(-17)*(8+4+2+1)/5 2^(-17)*(15)/5 = 2^(-17)*(3) So finally, (2^(-14) + 2^(-15) + 2^(-16) + 2^(-17))/5 is 3 time 2^(-17). I think It is simple and direct. but one should get the idea. It is wordy and looks complicated and let me be scared.

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