cv3t3l1na wrote:

The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5

B. 1/3

C. 2/5

D. 1/2

E. 2/3

Let weight of entire jar = \(W_T\) and weight after removing some beans = \(W_{TN}\)

and weight of beans = \(W_B\) and weight after removing some beans = \(W_{BN}\)

WEIGHT of jar = \(W_J = 20% of W_T\).......

so\(W_J = \frac{W_T}{5}.........W_B = \frac{4W_T}{5}........\)

if \(W_{TN} = \frac{6W_T}{10}.................W_J\)remains constant, so\(W_{BN} = W_{TN} - W_J =\frac{6W_T}{10} - \frac{W_T}{5} = \frac{2W_T}{5}.....\)

we are looking for fraction of what is left =\(\frac{W_{BN}}{W_B} = \frac{2W_T}{5}/\frac{4W_T}{5} = \frac{1}{2}\)

D

_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372

Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html