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The weight of a glass of jar is 20% of the weight of the jar

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The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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New post 25 Nov 2012, 03:42
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The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3
[Reveal] Spoiler: OA
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Re: The weight of a glass of jar is 20% of the weight of ... [#permalink]

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cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?
a.1/5
b.1/3
c.2/5
d.1/2
e.2/3


Somebody to suggest a way to solve this problem?


Let weight of jar filled with beans = 100 g
Weight of jar = 20 g
Weight of coffee beans = 80 g
Weight of jar and remaining beans = 60 g
Weight of remaining beans = 40 g

Fraction remaining = 40/80 = 1/2

Answer is D.

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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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New post 08 Jun 2016, 07:04
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cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3


Let weight of entire jar = \(W_T\) and weight after removing some beans = \(W_{TN}\)
and weight of beans = \(W_B\) and weight after removing some beans = \(W_{BN}\)
WEIGHT of jar = \(W_J = 20% of W_T\).......
so\(W_J = \frac{W_T}{5}.........W_B = \frac{4W_T}{5}........\)
if \(W_{TN} = \frac{6W_T}{10}.................W_J\)remains constant, so\(W_{BN} = W_{TN} - W_J =\frac{6W_T}{10} - \frac{W_T}{5} = \frac{2W_T}{5}.....\)

we are looking for fraction of what is left =\(\frac{W_{BN}}{W_B} = \frac{2W_T}{5}/\frac{4W_T}{5} = \frac{1}{2}\)

D
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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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New post 08 Jun 2016, 10:11
Initial weight of a jar with coffee beans: C
Weight of an empty jar: J = 0.2C
Initial weight of the coffee beans: = 1C - 0.2C = 0.8C

Weight of a jar with coffee beans after the removal: 0.6C
Weight of the cofee beans after the removal: 0.6C - 0.2C = 0.4C

So we know now that initially we had 0.8C and now only 0.4C: \(\frac{0.4}{0.8} = \frac{1}{2}\)

Answer: D
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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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New post 08 Jun 2016, 10:54
cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3



fraction part of the beans remain in the jar=(\(\frac{60}{100}\)-\(\frac{20}{100}\))/\(\frac{80}{100}\)=\(\frac{40}{100}\)*\(\frac{100}{80}\)=\(\frac{1}{2}\)

Correct Answer D
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Re: The weight of a glass of jar is 20% of the weight of the jar   [#permalink] 08 Jun 2016, 10:54
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