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The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Practice Questions Question: 33 Page: 277 Difficulty: 600

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The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

Say the weight of 1 dish of type X is \(x\) and the weight of 1 dish of type Y is \(y\). The question asks whether \(x<y\).

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y --> \(3x+2y<2x+4y\) --> \(x<2y\). If \(x=1\) and \(y=2\), then the answer is YES but if \(x=3\) and \(y=2\), then the answer is NO. Not sufficient.

(2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y --> \(4x+3y<3x+4y\) --> \(x<y\). Sufficient.

Re: The weights of all dishes of type X are exactly the same [#permalink]

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03 Sep 2012, 06:33

3

This post received KUDOS

Bunuel wrote:

The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Let X & Y are respective weights of Dish 1 & Dish 2. So Question reduces to is X<Y?

St 1: Insufficient: 3X + 2Y < 2X + 4Y, => X<2Y, Insufficient, X=4 & Y=5 or X=5 & Y=4 both conditions satisfy the equation.

St 2: Sufficient: 4X + 3Y < 3X + 4Y => X < Y, clearly sufficient.

Hence Answer is Option B.
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The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

Say the weight of 1 dish of type X is \(x\) and the weight of 1 dish of type Y is \(y\). The question asks whether \(x<y\).

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y --> \(3x+2y<2x+4y\) --> \(x<2y\). If \(x=1\) and \(y=2\), then the answer is YES but if \(x=3\) and \(y=2\), then the answer is NO. Not sufficient.

(2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y --> \(4x+3y<3x+4y\) --> \(x<y\). Sufficient.

Answer: B.

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: The weights of all dishes of type X are exactly the same [#permalink]

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22 Apr 2014, 21:57

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The weights of all dishes of type X are exactly the same [#permalink]

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23 May 2014, 15:29

Statement1: For those who hate picking numbers just like me: 3X + 2Y < 2X + 4Y --> x<2y --> x/2<y --> Thus y could be less than x, equal to x or greater than x. Not sufficient St2: is quite straight forward. Sufficient

B it is!
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Re: The weights of all dishes of type X are exactly the same [#permalink]

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10 Mar 2015, 18:00

I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient.

Re: The weights of all dishes of type X are exactly the same [#permalink]

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10 Mar 2015, 19:30

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mawus wrote:

I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient.

Based on your example,

Statement 1: X < 2Y

if x=2, and y=3 3 < 2*3 true 2<3 true

if x=3 and y=2 3 < 2*2 true but 3 is not < 2

we have 2 conflicting pieces of information, so Statement 1 is insufficient

Re: The weights of all dishes of type X are exactly the same [#permalink]

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09 May 2016, 14:51

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?

(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Solution:

We are given that we have two types of dishes, dish X and dish Y, and each dish of each type has the same weight. We are asked whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. If we let X and Y denote the weights of dishes X and Y, respectively, then we can restate the question as:

Is X < Y ?

Statement One Alone:

The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y.

Using the information from statement one we can set up the following inequality:

3X + 2Y < 2X + 4Y

X < 2Y

We see that the weight of 1 dish of type X is less than the combined weight of 2 dishes of type Y. However we can’t tell whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. This is not enough information to answer the question. We can eliminate answer choices A and D. Statement Two Alone:

The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.

Using the information from statement two we can set up the following inequality:

4X + 3Y < 3X + 4Y

X < Y

We see that this answers the question.

The answer is B.
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Re: The weights of all dishes of type X are exactly the same
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10 May 2016, 07:48

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