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The what is the value of t x u? (1) 5 x 6=9 (2) 7 x 1=3

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The what is the value of t x u? (1) 5 x 6=9 (2) 7 x 1=3 [#permalink] New post 09 Jul 2007, 03:41
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A
B
C
D
E

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The what is the value of t x u?

(1) 5 x 6=9
(2) 7 x 1=3

Last edited by nick_sun on 28 Jun 2008, 02:03, edited 1 time in total.
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 [#permalink] New post 09 Jul 2007, 04:58
D.

1) * represents only Addition (+) . SUFF. 1+0=1

2) * represents '+ ' or '-'. 1+0=1-0=1 SUFF.
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 [#permalink] New post 09 Jul 2007, 07:07
Any suggestions? :shock:

Last edited by nick_sun on 28 Jun 2008, 02:29, edited 1 time in total.
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 [#permalink] New post 09 Jul 2007, 07:44
I will go with D.

1. Suff : 0*2= 2 . therefore * should be + . 1*0 = 1+0 = 1

2 . Suff : 2*0 = 2. Therefore * could be either + or - . However we are asked 1*0 and hence 1+0 = 1-0 = 1. Hence Suff

Therefore D
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 [#permalink] New post 24 Jul 2007, 18:57
Anybody disagrees with D? it says OA is A in the set though.
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 [#permalink] New post 25 Jul 2007, 02:12
My Ans : A

0*2 = 2 is sufficient to know its addition
2*0 = 2 is insuffiicient to know whether its addition or subtraction

But, Thinking again after reading the answer choices, it probably doesnt matter whether its addition or subtraction if I have to find just 1*0... they both will yield the same result anyway.

So I am confused.
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 [#permalink] New post 25 Jul 2007, 07:53
D

0*2=2
* operator is + SUFF

2*0=2
* operator can be + or -

either one gives same result in the question. Hence SUFF
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 [#permalink] New post 25 Jul 2007, 08:11
yeah D makes sense...1*0 is always going to be 1...

i dont get why OA is A..
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 [#permalink] New post 25 Jul 2007, 23:41
St1:
If 0*2 = 2, then it must be +. So we can solve 1*0. Sufficient.

St2:
If 2*0 = 2, then * can be + or -. But no matter the sign, 1*0 will be 1. Sufficient.

Ans D

The answer is D because the question asks this: what is the value of 1*0? It is not asking what operation * denotes, so as long as you can get one value of 1*0, the statement is sufficient.
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Re: DS - operation* (GSet) [#permalink] New post 26 Jul 2007, 08:21
nick_sun wrote:
The operation* represents either addition, subtraction, or multiplication of integers, what is the value of 1*0?

(1) 0*2=2
(2) 2*0=2

a


Where's this q from? I remember seeing it somewhere....
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Re: DS - operation* (GSet) [#permalink] New post 26 Jul 2007, 10:04
nick_sun wrote:
The operation* represents either addition, subtraction, or multiplication of integers, what is the value of 1*0?

(1) 0*2=2
(2) 2*0=2

a



the reason could be that st 2 is not sufficient as it gives + and - but the fact is that it is sufficient whether it is - or +.

the originator might have thought it that with two different signs the answers would two different but its not true.

so D should be it.
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 [#permalink] New post 27 Jul 2007, 18:25
For (1)

0 * 2 = 2

0 + 2 = 2 & 2 - 0 = 2

for

1 * 0

0 + 1 = 1 but 0 - 1 = -1 why shouldn't we consider this.
  [#permalink] 27 Jul 2007, 18:25
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