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Re: There 4 balls - yellow, red, blue, and green. You pick two [#permalink]
4P2= 12 possible ways to select the balls (unless they are replaced after removal)

only 2 constraints exist: red/blue or blue/red

12-2= 10 ways

Or in terms of probability: 10/12--->5/6



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Re: There 4 balls - yellow, red, blue, and green. You pick two [#permalink]
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