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There 4 balls - yellow, red, blue, and green. You pick two

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Director
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There 4 balls - yellow, red, blue, and green. You pick two [#permalink] New post 24 Nov 2005, 04:43
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There 4 balls - yellow, red, blue, and green. You pick two of them. In how many cases one of the two is yellow or green?
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Auge um Auge, Zahn um Zahn :twisted: !

Director
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 [#permalink] New post 24 Nov 2005, 07:52
I just realised that is not probability that is asked.
So no of cases I think with yellow or green 10 out of the total 12.

Last edited by remgeo on 24 Nov 2005, 08:19, edited 2 times in total.
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Re: PS - Selecting balls [#permalink] New post 24 Nov 2005, 07:58
total = 4c2=6
not either yello or green = RB= 1
so the total possibilities = 6-1= 5, (YG is also considered the possibile case).
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 [#permalink] New post 24 Nov 2005, 08:02
4P2= 12 possible ways to select the balls (unless they are replaced after removal)

only 2 constraints exist: red/blue or blue/red

12-2= 10 ways

Or in terms of probability: 10/12--->5/6
  [#permalink] 24 Nov 2005, 08:02
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There 4 balls - yellow, red, blue, and green. You pick two

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