HarishV wrote:

There are 10 women and 3 men in Room A. One person is picked at random from Room A and moved to room B, where there are already 3 women and 5 men. If a single person is then used to be picked from Room B, what is the probability that a woman would be picked.

{Please try solving the problem using the Conditional Probability formula}....Would be very helpful to know how to determine the probability of 2 events when occurring simultaneously}

Using a tree diagram ( see the attachement)

Hence,

WW =

\frac{10}{13}*\frac{4}{9}=\frac{40}{117}MW =

\frac{3}{13}*\frac{3}{9}=\frac{9}{117}Finally, the probability that a woman would be picked is

P= \frac{40}{117} + \frac{9}{117}=\frac{49}{117}

Attachments

Prob.png [ 9.74 KiB | Viewed 1718 times ]

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