There are 11 women and 9 men in a committee : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 21 Jan 2017, 21:04

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# There are 11 women and 9 men in a committee

Author Message
Intern
Joined: 28 Jul 2005
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

There are 11 women and 9 men in a committee [#permalink]

### Show Tags

29 Sep 2005, 06:23
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:31) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are 11 women and 9 men in a committee. How many different groups of 4 can be formed consisting of 2 women and 2 men?
Current Student
Joined: 29 Jan 2005
Posts: 5238
Followers: 25

Kudos [?]: 377 [0], given: 0

### Show Tags

29 Sep 2005, 06:36
This is a multiple step combination problem so
11!/2!9! x 9!/2!7!= 1980
Senior Manager
Joined: 30 Oct 2004
Posts: 284
Followers: 1

Kudos [?]: 62 [0], given: 0

### Show Tags

29 Sep 2005, 06:46
I think...

2 W/M from 11/9 can be selected in 11C2*9C2 = 1980 ways
For the Group of 4, The 2 W/F can be arranged in 4C2*4C2 = 36 ways.
Different groups formed will be = 1980*36 = 71280
_________________

-Vikram

VP
Joined: 22 Aug 2005
Posts: 1120
Location: CA
Followers: 1

Kudos [?]: 102 [0], given: 0

### Show Tags

29 Sep 2005, 08:26
vikramm wrote:
I think...

2 W/M from 11/9 can be selected in 11C2*9C2 = 1980 ways
For the Group of 4, The 2 W/F can be arranged in 4C2*4C2 = 36 ways.
Different groups formed will be = 1980*36 = 71280

we dont need to rearrange 4 people two TWO groups of 2 person each.do we?
you right. 11C2 * 9C2 = 1980.
Manager
Joined: 03 Aug 2005
Posts: 134
Followers: 1

Kudos [?]: 2 [0], given: 0

### Show Tags

29 Sep 2005, 22:03
I also go for C(11,2)*C(9,2)

You do not need to arrange the groups of four, because no matter how you arrange it, it is still the same group.
Besides, if you were to arrange the groups of four, thay could be arranged in 4! different ways
29 Sep 2005, 22:03
Display posts from previous: Sort by