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There are 2 green, 3 red, and 2 blue balls in a box. 4 are

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Manager
Joined: 06 May 2005
Posts: 61
Location: India
Followers: 1

Kudos [?]: 9 [0], given: 0

There are 2 green, 3 red, and 2 blue balls in a box. 4 are [#permalink]

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12 May 2005, 03:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are 2 green, 3 red, and 2 blue balls in a box. 4 are drawn at random without replacement. What is the probability that of the 4 drawn balls two are red, 1 is green, and 1 is blue
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VP
Joined: 25 Nov 2004
Posts: 1493
Followers: 7

Kudos [?]: 98 [0], given: 0

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12 May 2005, 05:24
total = 7
no of balls drawn = 4
=[(3c2)(2c1)(2c1)]/7c4=(3x2x2)/35= 12/35
Director
Joined: 07 Jun 2004
Posts: 612
Location: PA
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Kudos [?]: 708 [0], given: 22

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13 May 2005, 02:37
yap same logic as above
13 May 2005, 02:37
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