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# There are 2 green, 3 red, and 2 blue balls in a box. 4 are

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Manager
Joined: 06 May 2005
Posts: 61
Location: India
Followers: 1

Kudos [?]: 3 [0], given: 0

There are 2 green, 3 red, and 2 blue balls in a box. 4 are [#permalink]  12 May 2005, 03:43
There are 2 green, 3 red, and 2 blue balls in a box. 4 are drawn at random without replacement. What is the probability that of the 4 drawn balls two are red, 1 is green, and 1 is blue
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VP
Joined: 25 Nov 2004
Posts: 1494
Followers: 6

Kudos [?]: 40 [0], given: 0

Re: Probability [#permalink]  12 May 2005, 05:24
total = 7
no of balls drawn = 4
=[(3c2)(2c1)(2c1)]/7c4=(3x2x2)/35= 12/35
Director
Joined: 07 Jun 2004
Posts: 614
Location: PA
Followers: 3

Kudos [?]: 316 [0], given: 22

yap same logic as above
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