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There are 2 green, 3 red, and 2 blue balls in a box. 4 are

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Manager
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Joined: 06 May 2005
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There are 2 green, 3 red, and 2 blue balls in a box. 4 are [#permalink] New post 12 May 2005, 03:43
There are 2 green, 3 red, and 2 blue balls in a box. 4 are drawn at random without replacement. What is the probability that of the 4 drawn balls two are red, 1 is green, and 1 is blue :?:
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Re: Probability [#permalink] New post 12 May 2005, 05:24
total = 7
no of balls drawn = 4
=[(3c2)(2c1)(2c1)]/7c4=(3x2x2)/35= 12/35
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 [#permalink] New post 13 May 2005, 02:37
yap same logic as above
  [#permalink] 13 May 2005, 02:37
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There are 2 green, 3 red, and 2 blue balls in a box. 4 are

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