Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 21 May 2013, 11:26
Customize  |  Hide

Search
Register
New posts
Unanswered

There are 20 workers in a firm. Five of them are to be sent

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Manager
Manager
Joined: 24 Jun 2003
Posts: 94
Location: Moscow
Followers: 1

Kudos [?]: 0 [0], given: 0

There are 20 workers in a firm. Five of them are to be sent [#permalink] New post 11 Aug 2003, 07:42
00:00

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
There are 20 workers in a firm. Five of them are to be sent on a mission. How many different groups could be formed, providing president, VP and accountant of the firm can't go all together among those five people?
Manager
Manager
Joined: 24 Jun 2003
Posts: 94
Location: Moscow
Followers: 1

Kudos [?]: 0 [0], given: 0

Re: Counting methods # 16 [#permalink] New post 11 Aug 2003, 23:52
Konstantin Lynov wrote:
There are 20 workers in a firm. Five of them are to be sent on a mission. How many different groups could be formed, providing president, VP and accountant of the firm can't go all together among those five people?


Close, but not quite.

Here is an approach:
There first part of the problem is done correctly by Mciato. We do need a total number of combinations and we need to decrease it by the number of groups where the President (P), Vice President (VP) and Accountant (A) serve together (a limiting condition).

The number of the teams that VP and P would serve together on is perhaps the hardest thing in this problem. Anyway, the trick is to count on how many teams P, VP and A will be. To do this, we need to imagine the group, and the five places in it: let’s assume that P is place #1 (since the order does not really matter), VP is # 2, A is # 3, and the two other places are available to the rest (17 total), so for the for the 4th place we can have 17 candidates, and the 5th place will be offered only to the remaining 16.
Thus, the total number of groups that P, VP and A would meet is 17C2 = 16*17/2*1=136.

Answer: 20C5-17C2=15504-136=15368
_________________

Respect,

KL

Re: Counting methods # 16   [#permalink] 11 Aug 2003, 23:52
    Similar topics Author Replies Last post
Similar
Topics:
 New posts A box contain 20 machine parts, 5 of them standard. A worker Avtar 7 10 Jun 2004, 18:08
New posts Shipping Clerk: The five specially ordered shipments sent kr8 3 08 Sep 2004, 17:01
New posts Shipping Clerk: The five specially ordered shipments sent drdas 1 03 Oct 2004, 16:02
New posts Shipping Clerk: The five specially ordered shipments sent chunjuwu 9 02 Feb 2005, 06:53
New posts Shipping Clerk: The five specially ordered shipments sent Puilunchristin 8 16 Jan 2006, 12:23
Display posts from previous: Sort by

There are 20 workers in a firm. Five of them are to be sent

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: Bunuel, VeritasPrepKarishma, IanStewart

Search for:


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com