Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 02 Jul 2015, 15:27

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# There are 3 green; 4 yellow; and 5 blue balls in a sack. 6

 Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Director
Joined: 12 Jun 2006
Posts: 534
Followers: 1

Kudos [?]: 34 [0], given: 1

There are 3 green; 4 yellow; and 5 blue balls in a sack. 6 [#permalink]  06 Feb 2007, 22:35
There are 3 green; 4 yellow; and 5 blue balls in a sack. 6 balls are taken at random w/o replacement. Find the prob to have 1 green; 2 yellow; and 3 blue balls.
Director
Joined: 05 Feb 2006
Posts: 899
Followers: 1

Kudos [?]: 54 [0], given: 0

[#permalink]  07 Feb 2007, 00:15
God this is time consuming question...
Manager
Joined: 10 Dec 2005
Posts: 112
Followers: 1

Kudos [?]: 3 [0], given: 0

Re: Prob prob II [#permalink]  07 Feb 2007, 14:45
ggarr wrote:
There are 3 green; 4 yellow; and 5 blue balls in a sack. 6 balls are taken at random w/o replacement. Find the prob to have 1 green; 2 yellow; and 3 blue balls.

The answer would be I think

3 * 6 * 10/12 * 11 * 9

5/33
_________________

"Live as if you were to die tomorrow. Learn as if you were to live forever." - Mahatma Gandhi

Senior Manager
Joined: 04 Jan 2006
Posts: 279
Followers: 1

Kudos [?]: 21 [0], given: 0

Re: Prob prob II [#permalink]  07 Feb 2007, 16:07
ggarr wrote:
There are 3 green; 4 yellow; and 5 blue balls in a sack. 6 balls are taken at random w/o replacement. Find the prob to have 1 green; 2 yellow; and 3 blue balls.

Let A = Having 1 green, 2 yellow, and 3 blue balls

Prob(A) = (Total ways to pick 1 Green, 2 Yellow, and 3 Blue)/(Total ways to pick 6 balls randomly)

Total ways to pick 6 balls randomly = 12C6
Total ways to pick 1 G, 2 Y, and 3B = (3C1) x (4C2) x (5C3)

Prob(A) = ((3C1) x (4C2) x (5C3))/12C6
= (3) x (2x3)x (5x2)/ (11 x 2 x 3 x 2 x 7)
= (3 x 5)/(11 x 7) = 15/77

15/77 is the answer for me.
Re: Prob prob II   [#permalink] 07 Feb 2007, 16:07
Similar topics Replies Last post
Similar
Topics:
there are 12 blue balls and y yellows balls. what is the 3 04 Nov 2007, 20:30
There are 50 balls. 20 are red, 20 are green, 6 are blue, 4 6 30 Aug 2007, 17:24
In an urn, there are 2 red balls, 3 blue balls, and 3 green 5 01 Dec 2006, 18:39
I have 4 types of marbles: Red: 3 Blue: 5 Green: 4 Cyan: 7 3 02 Sep 2006, 11:29
4 balls red, blue, green and black. If two balls are 1 09 Aug 2006, 00:31
Display posts from previous: Sort by

# There are 3 green; 4 yellow; and 5 blue balls in a sack. 6

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.