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There are 32 students in a certain class. The students chose

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VP
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Joined: 13 Jun 2004
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There are 32 students in a certain class. The students chose [#permalink] New post 17 Oct 2004, 19:57
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
There are 32 students in a certain class. The students chose some clubs to take part in, 10 students did not choose any club, 15 students chose A, 20 students chose B. How many students chose only one club?
Manager
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 [#permalink] New post 17 Oct 2004, 20:37
32-10 = 22 Students in one or two clubs

# In A + # In B =
15 + 20 = 35

35 - 22 = 13 In both A and B The overlap

22 - 13 = 9 In only one
VP
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Joined: 13 Jun 2004
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 [#permalink] New post 17 Oct 2004, 21:58
Correct.

I have the same result

A + B - Both + Excluded = 32
15+20-both+10=32
35-Both=22
Both=13

in A -> 15-13 = 2 students chose only A
in b -> 20-13 = 7 students chose only B

So total, 9 students only chose one club.

Good job Nzgmat :done
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 [#permalink] New post 18 Oct 2004, 21:39
as 10 students are not in any clubs
=> n(AUB) =32 - 10 =22

we have formula n(AUB) =n(A) + n(B) -n(A intersection B)

//**simple sets formula(cudn't find intersection's sign which is inverted U)..kindly adjust...

=>n(A intersection B)=15 + 20 - 22 = 13

so, only A=15 - 13 =2
and, only B=20 -13 =7

so only A& B = 2+7 =9
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VP
VP
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Joined: 13 Jun 2004
Posts: 1128
Location: London, UK
Schools: Tuck'08
Followers: 6

Kudos [?]: 21 [0], given: 0

GMAT Tests User
 [#permalink] New post 19 Oct 2004, 00:34
For me, exactly the same way than you guys to find that result is 9
Just wanted to confirm my first result because I didn't have any official answer attached with the problem :wink:
:done
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 [#permalink] New post 20 Oct 2004, 07:18
Who's up for a good Venn diagram?

Image

Ans: 9
Manager
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 [#permalink] New post 21 Oct 2004, 11:39
Same answer as everyone else, 9 people.

:-D
  [#permalink] 21 Oct 2004, 11:39
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There are 32 students in a certain class. The students chose

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