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Re: freshmen or a senior [#permalink]
02 Oct 2009, 23:54

Statement 1:Insufficient (easy to find out) Statement 2:F>7 Insufficient again.

1&2 together The only one situation that will comply with the two statments is: F=8 and S=34. Answer is C. Because if F=9 and S>4F...this will make the number of students larger than 42.

There are 42 students in a group. If each student is either a freshmen or a senior, how many of the students are seniors?

Given: S+F=42. Question: S=?

(1) The group has more than four times as many seniors as it has freshmen --> \(S>4F\) --> \(S>4*(42-S)\) --> \(S>33.6\). The number of seniors can be 34, 35, ... Not sufficient.

(2) The group has more than 7 freshmen --> \(F>7\) --> \(42-S>7\) --> \(S<35\). Not sufficient.

(1)+(2) \(S>33.6\) and \(S<35\) --> \(S=34\). Sufficient.

Re: freshmen or a senior [#permalink]
23 Apr 2011, 06:52

Statement 1 - Insufficient... Many answers are possible Statement 2 - Nothing can be derived from this

Both together - 35 & 7 is an option but from statement 2, more than 7 34 and 8 is possible (more than 4:1 and also 8) 33 and 9 is not possible as statement 1 is not satisfied

So only one answer when two statements considered together

Re: There are 42 students in a group. If each student is either [#permalink]
23 Nov 2013, 08:45

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Re: There are 42 students in a group. If each student is either [#permalink]
04 Dec 2013, 00:15

1

This post received KUDOS

TooLong150 wrote:

The translation of (1) killed me in this problem. I thought it meant 4s > f. Can someone help me translate it to s > 4f?

The statement clearly states that "more than four times as many seniors as it has freshmen." Lets forget more than part here and focus on four times as many seniors as it has freshmen. This means S=4F now more than part . incorporate > in place of =. So S > 4F

Re: There are 42 students in a group. If each student is either [#permalink]
04 Dec 2013, 00:22

2

This post received KUDOS

C.

Statement 1: s>4F

>4F+F = 42 F & S should be an integers. So I found factors of 42 fitting to solve the equation . Factors of 42 = 1,2,3,6,7,14,21,42. So 5F + F = 42 => F=7 & S = 35 6F+F= 42 => F = 6 & S=36. and so on for other values. => Not sufficient.

Statement 2: F>7. Many values satisfy this condition such as F = 8 & S = 34; F=9 & S = 33 & so on =>Insufficient

Re: There are 42 students in a group. If each student is either [#permalink]
21 Apr 2014, 07:23

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