Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Jun 2016, 12:11

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# There are 5 married couples and a group of three is to be

Author Message
Intern
Joined: 07 Aug 2003
Posts: 19
Location: USA
Followers: 0

Kudos [?]: 0 [0], given: 0

There are 5 married couples and a group of three is to be [#permalink]

### Show Tags

06 Dec 2003, 16:32
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?
CEO
Joined: 15 Aug 2003
Posts: 3461
Followers: 67

Kudos [?]: 804 [0], given: 781

### Show Tags

06 Dec 2003, 16:44
preyshi wrote:
There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?

if you mean "Arrangements" , its a totally different question.

i assume ,you meant # of ways to select three people so that a couple in not there in a group.

Required answer = total # of ways - # of ways in which a couple are in a group.

1. Total # of ways = 10C3 ( 5 couples...ten people) = 120

2. # of ways a couple can be selected = 5C1 * 8C1 = 40 ways

Select one couple out of the five ..and select one person out of the rest
of the 8.

3. required answer = 120 - 40 = 80 ways

EDIT : thanks BG... correction made with bold part

Last edited by Praetorian on 07 Dec 2003, 06:08, edited 2 times in total.
Director
Joined: 13 Nov 2003
Posts: 790
Location: BULGARIA
Followers: 1

Kudos [?]: 43 [0], given: 0

### Show Tags

07 Dec 2003, 03:42
Pret please note that : total arrangements 120. Arrangements with a couple are 40 (5C1 not 5C2, order is irrelevant ) so arrangements without couple are 80
Manager
Joined: 12 Oct 2003
Posts: 247
Location: USA
Followers: 1

Kudos [?]: 6 [0], given: 0

### Show Tags

07 Dec 2003, 09:38
I read the question itself in a diferent way.

i read it as "..a husband and wife may not be in ..." ... meaning husband and wife may be OR may not be.

same as in "I may not go there" .. it means I may OR may not go there.

Where am I going wrong here?
Display posts from previous: Sort by