There are 5 married couples and a group of three is to be

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30 Jan 2004, 18:19

* There are 5 married couples and a group of three is to be formed out of them; how many arrangements are there if a husband and wife may not be in the same group?
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30 Jan 2004, 18:25

C(10,3) = 120 (with no restrictions)

# ways to have a couple in the group of 3 = 5 * 8 = 40

Answer, I guess, is = 80

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30 Jan 2004, 18:45

Hmmmmmm I am getting 560.

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30 Jan 2004, 20:42

Hi, I am coming over from the 'other' test prep site. Found this question over there as well.

I agree with Zhung Gazi on this one.

10c3 yields 120 with no restrictions.

figuring how many groups can be formed with couples being apart of them, would be 5 * 8 or 40.

120 - 40 yields 80 distinct groups.

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04 Feb 2004, 04:25

Total Combinations :- 10C3=120
Ways in which one couple can be involved in the group is = 8
so for all couples it comes out to be = 5*8= 40

So total ways in which no couple is involved in the group = 120-40 = 80

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04 Feb 2004, 10:44

I guess the way to solve this would be

total-# of ways a husband and wife can be in a group

total - 10C3 = 120

Ways in which couple can be a part of the group 5*8 = 40

5 Couples we can choose 1 = 5C1 = 5
1 Person from the remaining 8 = 8C1 = 8

Ans : 120-40.

Please correct me If I am wrong

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04 Feb 2004, 21:37

Pakoo u r right...

Vivek.
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[#permalink] 04 Feb 2004, 21:37

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There are 5 married couples and a group of three is to be

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There are 5 married couples and a group of three is to be

There are 5 married couples and a group of three is to be

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