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There are 5 white plates and 1 blue plate in a circle, with [#permalink]
13 Mar 2008, 16:34
There are 5 white plates and 1 blue plate in a circle, with only one of 6 different foods in each plate. Among the foods, there are peanuts and raisins, how many arrangements are there if the blue plate only contains peanuts or raisins?
Re: Combination problem [#permalink]
13 Mar 2008, 17:22
With Peanuts in blue plate remaining foods can be arranged in 5! ways. Similary with raisins in blue plate too. so total number of combinations is 5!+5! = 240. If the plates are not circular the answer would be different because we don't need to keep them in the order.