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# There are 50 employees in the office of ABC Company. Of

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Joined: 22 Oct 2012
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There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Nov 2012, 07:36
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Difficulty:

35% (medium)

Question Stats:

70% (02:19) correct 30% (01:49) wrong based on 269 sessions

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There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 1 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?

A. 0
B. 9
C. 10
D. 11
E. 26
[Reveal] Spoiler: OA

Last edited by Bunuel on 23 Nov 2012, 07:44, edited 1 time in total.
Renamed the topic and edited the question.
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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Nov 2012, 08:05
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cv3t3l1na wrote:
There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 1 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?

A. 0
B. 9
C. 10
D. 11
E. 26

50 = 22 + 15 + 14 - 9 - 1*2 + x

x = 10

Kudos Please... If my post helped.
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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Nov 2012, 09:39
MacFauz wrote:
cv3t3l1na wrote:
There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 1 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?

A. 0
B. 9
C. 10
D. 11
E. 26

50 = 22 + 15 + 14 - 9 - 1*2 + x

x = 10

Kudos Please... If my post helped.

Hii MacFauz.
I got confused with the formula applied.
Isn't it Total-neither=A+B+C-A(intersection)B-B(intersection)C-C(intersection)A+A(intersection)B(intersection)C ?
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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Nov 2012, 09:53
1
KUDOS
Expert's post
Marcab wrote:
MacFauz wrote:
cv3t3l1na wrote:
There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 1 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?

A. 0
B. 9
C. 10
D. 11
E. 26

50 = 22 + 15 + 14 - 9 - 1*2 + x

x = 10

Kudos Please... If my post helped.

Hii MacFauz.
I got confused with the formula applied.
Isn't it Total-neither=A+B+C-A(intersection)B-B(intersection)C-C(intersection)A+A(intersection)B(intersection)C ?

Hope it helps.
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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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20 Dec 2013, 02:08
50 Employees. Counting every "different" attendand to the courses we have:

Accounting: 22
Finance: 15
Marketing: 14

Which would add up to 51 "different" attendands, which is not possible.
Now 9 have taken exactly 2 courses, which means that there are 9 less "different" attendands. Say that 9 of the Finance attentands also attended Accounting.
51-9= 42

1 Person has taken all three courses. As above, we subtract him from the number of "different" attendands. Since this time the person took all three courses, we have to substract him two times.
42-2= 40.

This tells us that we had 40 "different" attendands and 10 employees who didn't take any courses.

Hope it helps.

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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Feb 2015, 18:45
Hii MacFauz.
I got confused with the formula applied.
Isn't it Total-neither=A+B+C-A(intersection)B-B(intersection)C-C(intersection)A+A(intersection)B(intersection)C ?
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Re: There are 50 employees in the office of ABC Company. Of [#permalink]

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23 Feb 2015, 21:28
Hi Bingo123,

In this variation on the question, you have to account for the employees who have taken none of the courses. You can either subtract that group from the total OR add that group to the sum of the other groups. The net effect on the calculation will be the same.

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# Special Offer: Save $75 + GMAT Club Tests 60-point improvement guarantee www.empowergmat.com/ ***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*********************** SVP Status: The Best Or Nothing Joined: 27 Dec 2012 Posts: 1858 Location: India Concentration: General Management, Technology WE: Information Technology (Computer Software) Followers: 47 Kudos [?]: 1935 [0], given: 193 Re: There are 50 employees in the office of ABC Company. Of [#permalink] ### Show Tags 24 Feb 2015, 00:11 Refer diagram below: Attachment: overla.png [ 7.37 KiB | Viewed 3109 times ] We require to find value of x (yellow shaded region) Given that a+b+c = 9 Setting up the equation 22 + 13 - (a+c) + c + 14 - (b+c) + x = 50 x - 9 = 1 x = 10 Answer = C _________________ Kindly press "+1 Kudos" to appreciate Intern Joined: 23 Dec 2014 Posts: 16 Followers: 0 Kudos [?]: 8 [0], given: 49 Re: There are 50 employees in the office of ABC Company. Of [#permalink] ### Show Tags 25 Feb 2015, 18:24 Hello Rich, Thanks for you response. However, my point is not about the employees who have taken none of the courses. Instead, for about the employees who have taken all the courses. ( -1*2 in the below equation). 50 = 22 + 15 + 14 - 9 - 1*2 + x x = 10 As per my knowledge, we should add (1 time) the employees who have taken all the courses. However, what i see in the solution is that we are subtracting (2 times) the same. This is completely against the logic and formula. Kindly help to explain. Thanks. EMPOWERgmat Instructor Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 8304 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: 340 Q170 V170 Followers: 381 Kudos [?]: 2465 [1] , given: 163 Re: There are 50 employees in the office of ABC Company. Of [#permalink] ### Show Tags 25 Feb 2015, 21:24 1 This post received KUDOS Expert's post 1 This post was BOOKMARKED Hi Bingo123, If someone has taken ALL 3 courses, then that person has been counted 3 times (once in accounting, once in finance and once in marketing), but each person is only supposed to counted once in total. As such, you have to subtract 2 of those "counts" from the calculation. GMAT assassins aren't born, they're made, Rich _________________ # Rich Cohen Co-Founder & GMAT Assassin # Special Offer: Save$75 + GMAT Club Tests

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There are 50 employees in the office of ABC Company. Of [#permalink]

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26 Feb 2015, 18:11
Hello Rich,

Thanks for your response.I now understand my mistake of ignoring the word "EXACTLY" in 2 courses.

The established formula of 3 sets takes it as " At least 2 courses" which is why it adds"All Courses" once.

Thanks.
There are 50 employees in the office of ABC Company. Of   [#permalink] 26 Feb 2015, 18:11
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