Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

There are 8 teams in a certain league and each team plays [#permalink]
10 May 2012, 20:45

6

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

15% (low)

Question Stats:

66% (01:59) correct
34% (00:40) wrong based on 181 sessions

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

Re: There are 8 teams in a certain league and each team plays... [#permalink]
10 May 2012, 21:16

IMO 54 matches

Let's say first team plays with 7 other teams - resulting in 7 matches, taking this further in the similar way, the number of matches between 8 teams would be 7+6+5+4+3+2+1 = 28.. as in this case each team is playing with other twice, the no of matches would be 28*2 = 56

Last edited by gmihir on 11 May 2012, 00:13, edited 1 time in total.

Re: There are 8 teams in a certain league and each team plays... [#permalink]
10 May 2012, 21:19

Every team plays with 7 teams...so total no of matches = 8 x 7 = 56. Now, each match is played twice => 56 x 2 But 2 teams play a match => 56 x 2 /2 = 56.

Re: There are 8 teams in a certain league and each team plays [#permalink]
10 May 2012, 21:37

1

This post received KUDOS

Expert's post

2

This post was BOOKMARKED

Smita04 wrote:

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

A. 15 B. 16 C. 28 D. 56 E. 64

# of different pairs possible from 8 teams is \(C^2_{8}=28\), since each pair plays twice between each other than total # of games is 2*28=56.

Re: There are 8 teams in a certain league and each team plays [#permalink]
14 Sep 2013, 09:44

Thanks Bunuel! I caught my mistake. I was looking for other ways of solving question 133 OG 13th edi (121 in 12th edi), and that is how I landed here. Similar version of this question in the 13th and 12th edi OGs has the word 'once' instead of 'twice', as in the above question. My bad !! Is my approach at solving the question correct?

Re: There are 8 teams in a certain league and each team plays [#permalink]
14 Sep 2013, 09:55

Expert's post

vjns wrote:

Thanks Bunuel! I caught my mistake. I was looking for other ways of solving question 133 OG 13th edi (121 in 12th edi), and that is how I landed here. Similar version of this question in the 13th and 12th edi OGs has the word 'once' instead of 'twice', as in the above question. My bad !! Is my approach at solving the question correct?

Re: There are 8 teams in a certain league and each team plays [#permalink]
23 Aug 2014, 10:11

Bunuel wrote:

Smita04 wrote:

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

A. 15 B. 16 C. 28 D. 56 E. 64

# of different pairs possible from 8 teams is \(C^2_{8}=28\), since each pair plays twice between each other than total # of games is 2*28=56.

Answer: D.

I'm a little confused here -- why are we using the combination formula and NOT the permutation formula. We don't really care for these teams to be arranged alphabetically. Similar to if the letters are to be arranged alphabetically, meaning, ab, ac, ad, bc, bd, then we would use combination. But we don't care if team D plays B vs. team B playing team D. Since order is NOT important, wouldn't we use permutation.

There were a few similar problems: 1) How many 2 letters words can be made out of ABCD and in alphabetical order - 2C4 = 6 2) How many unique 4 letter words can be made from 10 letters but ABCDE and EDCBA are considered different = 10P4 = 10!/6!

Doesn't this question fall into the Permutation area?

Re: There are 8 teams in a certain league and each team plays [#permalink]
18 Sep 2015, 09:47

Bunuel wrote:

Smita04 wrote:

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

A. 15 B. 16 C. 28 D. 56 E. 64

# of different pairs possible from 8 teams is \(C^2_{8}=28\), since each pair plays twice between each other than total # of games is 2*28=56.

Answer: D.

Can you show the calculation for 28? I am confused for the formula of combination. Shouldn't it be 8C2?

Any possible theory on this from GMATCLUB? _________________

Kindly support by giving Kudos, if my post helped you!

Re: There are 8 teams in a certain league and each team plays [#permalink]
19 Sep 2015, 06:03

harishbiyani8888 wrote:

Bunuel wrote:

Smita04 wrote:

There are 8 teams in a certain league and each team plays each of the other teams exactly twice. If each game is played by 2 teams, what is the total number of games played?

A. 15 B. 16 C. 28 D. 56 E. 64

# of different pairs possible from 8 teams is \(C^2_{8}=28\), since each pair plays twice between each other than total # of games is 2*28=56.

Answer: D.

Can you show the calculation for 28? I am confused for the formula of combination. Shouldn't it be 8C2?

Any possible theory on this from GMATCLUB?

It is 8C2. It is thee number of ways in which 2 teams can be selected out of 8.

\(nCr = \frac{n!}{(n-r)!(r!)\)

\(8C2 = \frac{8!}{(8-2)!(2!)\)

= \(\frac{8*7*6!}{6!*2!}\) = \(\frac{8*7}{2*1}\)

=28

These are the total number of matches 8 teams can play when each team plays 1 match against all the other teams. Each team plays 2 matches. So total number of matches each team plays is 28*2 = 56

Low GPA MBA Acceptance Rate Analysis Many applicants worry about applying to business school if they have a low GPA. I analyzed the low GPA MBA acceptance rate at...

Every student has a predefined notion about a MBA degree:- hefty packages, good job opportunities, improvement in position and salaries but how many really know the journey of becoming...