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There are 8 teams in a certain league and each team plays [#permalink]
17 Jun 2012, 03:52
Question Stats:
78% (01:41) correct
21% (00:22) wrong based on 26 sessions
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played? A. 15 B. 16 C. 28 D. 56 E. 64
Last edited by Bunuel on 17 Jun 2012, 03:56, edited 1 time in total.
Edited the question and added the OA.
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Re: There are 8 teams in a certain league and each team plays [#permalink]
17 Jun 2012, 03:57
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Re: There are 8 teams in a certain league and each team plays [#permalink]
14 Nov 2012, 06:23
Bunuel wrote: sarb wrote: There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?
A. 15 B. 16 C. 28 D. 56 E. 64 The total # of games played would be equal to the # of different pairs possible from 8 teams, which is C^2_{8}=28. Answer: C. P.S. Please read and follow: rules-for-posting-please-read-this-before-posting-133935.html Pay attention ot the points #3 and #8. I would like to learn about C^2_{8}=28. Manhattan Book doesn't discuss this approach. They have anagram approach.
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Re: There are 8 teams in a certain league and each team plays [#permalink]
15 Nov 2012, 23:27
Hi Bunnel,
I would also like to learn this approach. Can u help me?
Sree
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Re: There are 8 teams in a certain league and each team plays [#permalink]
16 Nov 2012, 04:19
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Re: There are 8 teams in a certain league and each team plays [#permalink]
18 Nov 2012, 21:09
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These type of problems can be solved with a simple diagram.
1. Draw a table consisting of 8 columns and 8 rows. 2. Divide the table by a diagonal and count the number of spaces including the half spaces only on one side of the diagonal. 3. The number should be 28.
I tried uploading the diagram but unsuccessful.
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Re: There are 8 teams in a certain league and each team plays [#permalink]
28 Dec 2012, 06:59
sarb wrote: There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?
A. 15 B. 16 C. 28 D. 56 E. 64 =\frac{8!}{2!6!}=4*7 = 28Answer: C
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Re: There are 8 teams in a certain league and each team plays [#permalink]
31 Jan 2013, 01:37
it is not easy and is harder if we are on the test date.
there are 8 team to take out 2 teams, IF ORDER MATTERS we have 8*7 but in fact order does not matter
8*7/2=28
princeton gmat book explain this point wonderfully.
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Re: There are 8 teams in a certain league and each team plays [#permalink]
16 May 2013, 01:13
Bunuel wrote: The total # of games played would be equal to the # of different pairs possible from 8 teams, which is C^2_{8}=28.
Hi Bunuel, I have seen that you are using this formula/approach to solve most of the combination questions. Could you please explain, in general, how do you use this formula? Thanks a lot.
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Re: There are 8 teams in a certain league and each team plays [#permalink]
16 May 2013, 04:33
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Re: There are 8 teams in a certain league and each team plays [#permalink]
17 May 2013, 21:18
pranav123 wrote: These type of problems can be solved with a simple diagram.
1. Draw a table consisting of 8 columns and 8 rows. 2. Divide the table by a diagonal and count the number of spaces including the half spaces only on one side of the diagonal. 3. The number should be 28.
I tried uploading the diagram but unsuccessful. That's one of those tips that can make my life easier. I'm book marking this page. Thanks.
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Re: There are 8 teams in a certain league and each team plays
[#permalink]
17 May 2013, 21:18
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