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There are a total of 19 students in Mr. Schmidt's gym class. Over the [#permalink]

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19 Jun 2011, 23:27

00:00

A

B

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Difficulty:

25% (medium)

Question Stats:

89% (01:40) correct
11% (00:00) wrong based on 9 sessions

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There are a total of 19 students in Mr. Schmidt's gym class. Over the course of a badminton unit, each of the 19 students will compete exactly once against every other student in the class. How many total games of badminton will be played?

Re: There are a total of 19 students in Mr. Schmidt's gym class. Over the [#permalink]

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20 Jun 2011, 02:04

guygmat wrote:

There are a total of 19 students in Mr. Schmidt's gym class. Over the course of a badminton unit, each of the 19 students will compete exactly once against every other student in the class. How many total games of badminton will be played?

Re: There are a total of 19 students in Mr. Schmidt's gym class. Over the [#permalink]

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20 Jun 2011, 02:18

guygmat wrote:

There are a total of 19 students in Mr. Schmidt's gym class. Over the course of a badminton unit, each of the 19 students will compete exactly once against every other student in the class. How many total games of badminton will be played?

A)38 B)171 C)190 D)210 E)361

my answer B

here we go!

19*19=361

361-19=342 number of games wich teams played with each other (2 times with each) 342/2=171 number of games which play for 1 game with each other.

Re: There are a total of 19 students in Mr. Schmidt's gym class. Over the [#permalink]

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21 Jun 2011, 11:12

I would calculate this way- first Student will have chance to play 18 games (given the condn that one can have only one game with the other student), second will have 17 games, third will have 16 games and so on...

So all the # games would be sum of the series 1+2+ .....+18= (1+18)*18/2= 171 so B it is! Let me know if there's any disconnect!
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