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There are four contestants in the competition for 6

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Intern
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There are four contestants in the competition for 6 [#permalink] New post 18 Sep 2003, 14:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are four contestants in the competition for 6 different prizes. A contestant can win only one prize. How many different outcomes are possible at the competition for the four contestants?

A) 15

B) 30

C) 60

D) 180

E) 360
Senior Manager
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 [#permalink] New post 21 Sep 2003, 08:55
Is it A?

6*5*4*3/4! = 15
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 [#permalink] New post 21 Sep 2003, 15:29
I think it's a permutation. I'd choose E.
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 [#permalink] New post 03 Nov 2003, 11:06
I think the correct answer is D.

Just try to imagine putting 4 ppl into 6 seats. where the four ppl can choose any of the 6 seats.

So its 6P4...OR 180.


my 2 cents....
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 [#permalink] New post 03 Nov 2003, 12:07
sudzpwc wrote:
I think the correct answer is D.

Just try to imagine putting 4 ppl into 6 seats. where the four ppl can choose any of the 6 seats.

So its 6P4...OR 180.


my 2 cents....


6P4 is = 360 (NOT 180) So the answer would be E.
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 [#permalink] New post 03 Nov 2003, 13:34
am,
my bad...silly mistake in cacl....
thanks though.
sudz
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 [#permalink] New post 14 Jan 2004, 19:48
I did it this way.
Assume we have to seat 4 people in 6 chairs.
so Chose 4 seats first = 6C4 = 15
then 4 people can seat in 4! ways
so total ways = 6C4 * 4! = 15*24 = 360
  [#permalink] 14 Jan 2004, 19:48
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There are four contestants in the competition for 6

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